Help on a question regarding the stereoisomerism of a cyclic compound.
I have come across a question in a textbook which asks to identify how many stereo isomers are possible for a displayed organic compound (attached below).
The answer states that there would be 4 stereoisomers and gives the following explanation:
"The stereoisomers with the skeletal formula shown will all be Z isomers. There will be (+) and (−) isomers at both the chiral centres ; therefore four stereoisomers; with the skeletal formula shown."
I do not understand why the skeletal formula shows will only be z isomers? Does anyone understand this?
The answer states that there would be 4 stereoisomers and gives the following explanation:
"The stereoisomers with the skeletal formula shown will all be Z isomers. There will be (+) and (−) isomers at both the chiral centres ; therefore four stereoisomers; with the skeletal formula shown."
I do not understand why the skeletal formula shows will only be z isomers? Does anyone understand this?
(edited 11 months ago)
Because both the highest priority groups are on the same side of the double bond
Original post by Emmmaaaa...
Because both the highest priority groups are on the same side of the double bond
This does make sense for the alkene group, however how would you know the cis-trans arrangement of the two groups attached to the cyclic alkane?
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