Im struggling with dilution calculations for the following write up, can someone help?
- Stock solution of KI/potassium iodate at 1000 μg I/g prepared with water and NaOH(1:4v/v) . - Diluted with water to 1 μg I/g - Te standard (1000 ug Te/mL in 2-3% HNO3) was diluted to 1 ug Te/g and further dilute to 100 ng Te/g before adding to samples