UCAT Medentry QR Question

charlotte05x

Hi, could someone please explain a logical way of answering this question. Many thanks! Screenshot (404).png

(edited 8 months ago)

Reply 1

TSR Hippocrates

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Reply 2

GANFYD

Original post by charlotte05x

Hi, could someone please explain a logical way of answering this question. Many thanks! Screenshot (404).png

Work out how fast Amy is running.
We know Daniel is running the same speed initially, so work out how far he has run in 15.75 minutes.
Then work out how long it will take him to run that distance at 13.3km/hr

And don't forget to get back to mins and secs at the end!

Reply 3

Davelad42

As he was initially running at the same speed as Amy, we have to work that out, so take the distance/time (converting minutes to hours for km/hr) 4.375/(31.5 /60) = 8.33...km/hr.
As we now know how long he ran for (in the q) towards B from A and his and Amy's joint speed we can calculate the distance travelled (once again converting minutes to hours): (15.75/60) x 8.33... = 2.1875km.
We now have the distance from A when he turns around to run back and his new faster pace (13.3km/hr in the q) so do distance/speed for the time taken:
2.1875/13.3 = 0.164474 hours - x60 to convert to minutes = 9.86844 -> 9 minutes + (convert the seconds) .86844 x 60 =52.1064 seconds.
Just did this rough so possibly not exact with rounding errors but it simplifies to 9 mins 52s to the nearest second.
Good luck with the ucat!