Exactly, so find the moles of HCl initially, then find the new concentration with 125cm3 as the new volume. Now you have [HCl] which = [H+] so you can use pH = -log[H+]
Exactly, so find the moles of HCl initially, then find the new concentration with 125cm3 as the new volume. Now you have [HCl] which = [H+] so you can use pH = -log[H+]