Urgent help rearranging this please
Hi, I don't actually take a-level maths but I do A2 physics and I'm really struggling at the moment. Could someone please help me rearranged this formula...
Basically, we plot a graph of V/t and calculate a gradient.
We're then given the equation:
V=V0e-t/RC
We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.
Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.
I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions.
Thank you sooooo much! 
x
Basically, we plot a graph of V/t and calculate a gradient.
We're then given the equation:
V=V0e-t/RC
We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.
Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.
I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions.
Thank you sooooo much! xOriginal post by Sparkliest
Hi, I don't actually take a-level maths but I do A2 physics and I'm really struggling at the moment. Could someone please help me rearranged this formula...
Basically, we plot a graph of V/t and calculate a gradient.
We're then given the equation:
V=V0e-t/RC
We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.
Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.
I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions. Thank you sooooo much! x
Basically, we plot a graph of V/t and calculate a gradient.
We're then given the equation:
V=V0e-t/RC
We know the value for our gradient (V/t), V0 and R. We need to rearrange the equation to get the value for C.
Everyone in my class does a-level maths and I know they ln it all and use y=mx+c but I don't really understand the relevance of that.
I'd be so grateful for any help on this. I have an accessed practical soon and I need to be able to find the value of C from the above data myself in exam conditions.
Thank you sooooo much! xso
Solve for C
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