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Differentiation help

HumiT

Hi,

How do you differentiate this

f(x) = 6x+3+sqrt x /x^2

Thanks

Reply 1

uberteknik

Original post by HumiT

Hi,

How do you differentiate this

f(x) = 6x+3+sqrt x /x^2

Thanks

Convert sqrt x / x²using the rules of indices then differentiate as normal.

i.e. a^m x aⁿ= a^m+nand a^m/aⁿ = a^m-n
Remember sqrt(x) = x^1/2

(edited 11 years ago)

Duhh..thanks :smile:

Original post by HumiT

Duhh..thanks :smile:

remember root 2 is equal to

Unparseable latex formula:

2^1^/^2

(edited 11 years ago)

Reply 4

Joshmeid

Original post by upthegunners

remember root 2 is equal to

Unparseable latex formula:

x^1^/^2

\sqrt{2} \not= x^{\frac{1}{2}}

Posted from TSR Mobile

Reply 5

2710

Original post by upthegunners

remember root 2 is equal to 2^(1/2)

Corrected

Reply 6

upthegunners

Original post by Joshmeid

\sqrt{2} \not= x^{\frac{1}{2}}

Posted from TSR Mobile

bleh.. you know I meant that

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Differentiation help

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