What mass of sodium carbonate would be required to prepare 250 ml of 0.1 M sodium car
What mass of sodium carbonate would be required to prepare 250 ml of 0.1 M sodium carbonate?
please help and explain it to me, i really dont understand
please help and explain it to me, i really dont understand
Original post by wag12k12dunkno
What mass of sodium carbonate would be required to prepare 250 ml of 0.1 M sodium carbonate?
please help and explain it to me, i really dont understand
please help and explain it to me, i really dont understand
Okay, so here is how you do it
First, you find the moles of sodium carbonate in the given solution.
moles=concentraton x volume (n=cv)
=0.1mol/dm3 x (250/1000)dm3
(0.1M = 0.1mol/dm3 and converting 250ml into dm3 by dividing by 1000)
=0.025mol
Next, you find out the molecular mass of Na2CO3=
( 23 x 2) + 12 + (16 x 3)
= 46 + 12 + 48
=106 (g/mol)
Then, you find out the mass of Na2CO3 needed to give .025 mol (the amount of moles in the solution)
moles= mass / molar mass
Therefore, mass = moles X molar mass
=0.025 x 106
2.65g
Hope this helps
Original post by Munrot07
you have a volume and a concentration so work out the moles n = (C x V)/1000
Then work out the mass m = n x Mr (you know that sodium carbonate is NaCO3 so use the periodic table to work out the Mr)
Then work out the mass m = n x Mr (you know that sodium carbonate is NaCO3 so use the periodic table to work out the Mr)
thanks but isnt sodium carbonate na2co3 and so will it be 0.025*106=2.56g! and also can you explain how it all works
Original post by 4evershinee
Okay, so here is how you do it
First, you find the moles of sodium carbonate in the given solution.
moles=concentraton x volume (n=cv)
=0.1mol/dm3 x (250/1000)dm3
(0.1M = 0.1mol/dm3 and converting 250ml into dm3 by dividing by 1000)
=0.025mol
Next, you find out the molecular mass of Na2CO3=
( 23 x 2) + 12 + (16 x 3)
= 46 + 12 + 48
=106 (g/mol)
Then, you find out the mass of Na2CO3 needed to give .025 mol (the amount of moles in the solution)
moles= mass / molar mass
Therefore, mass = moles X molar mass
=0.025 x 106
2.65g
Hope this helps
First, you find the moles of sodium carbonate in the given solution.
moles=concentraton x volume (n=cv)
=0.1mol/dm3 x (250/1000)dm3
(0.1M = 0.1mol/dm3 and converting 250ml into dm3 by dividing by 1000)
=0.025mol
Next, you find out the molecular mass of Na2CO3=
( 23 x 2) + 12 + (16 x 3)
= 46 + 12 + 48
=106 (g/mol)
Then, you find out the mass of Na2CO3 needed to give .025 mol (the amount of moles in the solution)
moles= mass / molar mass
Therefore, mass = moles X molar mass
=0.025 x 106
2.65g
Hope this helps
thanks so much! i just did it before the reply but this was very clear, cheers
Original post by wag12k12dunkno
thanks so much! i just did it before the reply but this was very clear, cheers
No probs
Original post by 4evershinee
No probs
What mass of calcium chloride would be required to prepare 2 litres of 0.5 M calcium chloride
So do i find out the moles so (2*0.5)/1000= 0.001
so then moles= mass/molar mass
so mass= moles* molar mass
molar mass of cacl2 is 111
so 0.001*111= 0.111
i know iv gone wrong somewhere here
Original post by Munrot07
you have a volume and a concentration so work out the moles n = (C x V)/1000
Then work out the mass m = n x Mr (you know that sodium carbonate is Na2CO3 so use the periodic table to work out the Mr)
Then work out the mass m = n x Mr (you know that sodium carbonate is Na2CO3 so use the periodic table to work out the Mr)
please help with next question im not sure where i went wrong i dont know if i had to divide by 1000 or not
Original post by wag12k12dunkno
What mass of calcium chloride would be required to prepare 2 litres of 0.5 M calcium chloride
So do i find out the moles so (2*0.5)/1000= 0.001
so then moles= mass/molar mass
so mass= moles* molar mass
molar mass of cacl2 is 111
so 0.001*111= 0.111
i know iv gone wrong somewhere here
So do i find out the moles so (2*0.5)/1000= 0.001
so then moles= mass/molar mass
so mass= moles* molar mass
molar mass of cacl2 is 111
so 0.001*111= 0.111
i know iv gone wrong somewhere here
convert L to ML = 2L = 2000ML
2000 X 0.5/1000= 1
1 x 111 = 111
Remember that ml=cm3 they're both the same.
Original post by wag12k12dunkno
please help with next question im not sure where i went wrong i dont know if i had to divide by 1000 or not
you only divide by 1000 if you have cm^3 because you need it in dm^3. If the volume is in dm^3 do not divide by 1000. 1dm^3 = 1 litre
Original post by cleveradam
convert L to ML = 2L = 2000ML
2000 X 0.5/1000= 1
1 x 111 = 111
Remember that ml=cm3 they're both the same.
2000 X 0.5/1000= 1
1 x 111 = 111
Remember that ml=cm3 they're both the same.
why do i have to convert L to ML in the last question i just divided by 1000
Original post by Munrot07
you only divide by 1000 if you have cm^3 because you need it in dm^3. If the volume is in dm^3 do not divide by 1000. 1dm^3 = 1 litre
ok cheers
Original post by Munrot07
you only divide by 1000 if you have cm^3 because you need it in dm^3. If the volume is in dm^3 do not divide by 1000. 1dm^3 = 1 litre
how do i find the number of moles in an element if im given the amount of grams of the element
moles= mass/molar mass dw i was being dumb
(edited 10 years ago)
Original post by Munrot07
you only divide by 1000 if you have cm^3 because you need it in dm^3. If the volume is in dm^3 do not divide by 1000. 1dm^3 = 1 litre
dw i worked it out
(edited 10 years ago)
Original post by wag12k12dunkno
thanks so much! i just did it before the reply but this was very clear, cheers
You need to prepare 2.500 L of 1M sodium carbonate. What mass of sodium carbonate is required for this solution?
can u fix this one?
Original post by mrcullen
You need to prepare 2.500 L of 1M sodium carbonate. What mass of sodium carbonate is required for this solution?
can u fix this one?
can u fix this one?
I just tried many times and I got incorrect
the mass for Na2CO3. 105.99 g/mol
and I got for my question 264.975 g/mol so could check out for me please ?
Original post by mrcullen
You need to prepare 2.500 L of 1M sodium carbonate. What mass of sodium carbonate is required for this solution?
can u fix this one?
can u fix this one?
I just tried many times and I got incorrect
the mass for Na2CO3. 105.99 g/mol
and I got for my question 264.975 g/mol so could check out for me please ?
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