How to find constants of quadratic equation given the coordinates.

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Yes i do.
Lol feel like im getting married.

Now multiply both sides by

2x

, what do you get? :biggrin:

Now multiply both sides by

2x

, what do you get? :biggrin:

AAAAAAAAAHHHHHHHHH......

5 million years later

hhhhhhhhh.
I get as you said .

AAAAAAAAAHHHHHHHHH......

5 million years later

hhhhhhhhh.
I get as you said .

You're missing the

\frac{dy}{dx}

, but I think you've gotten it. :biggrin:

To recap:

\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \frac{2x}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \sqrt{x} \Rightarrow 2x\frac{dy}{dx} = y

You're missing the

\frac{dy}{dx}

, but I think you've gotten it. :biggrin:

To recap:

\displaystyle \frac{dy}{dx} = \frac{1}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \frac{2x}{2\sqrt{x}} \Rightarrow 2x \frac{dy}{dx} = \sqrt{x} \Rightarrow 2x\frac{dy}{dx} = y

Yes that explains it perfectly. Sometimes you just need some Zacken in your head to see things more clearly.

Yes that explains it perfectly. Sometimes you just need some Zacken in your head to see things more clearly.

Awesome, I'm off to bed now - see you around. :-)

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