EVEN MOAR enthalpy problems
how to do question 2 part c?
@Samba123 @EricPiphany
@Samba123 @EricPiphany
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Original post by thefatone
Magnesium becomes limiting reagent (also your tags don't work)
Original post by thefatone
How much Cu reacts? And you know the molar enthalpy change of the reaction already.
Original post by samb1234
Magnesium becomes limiting reagent (also your tags don't work)
right so turns out when you edit tags in they don't work, beautiful. i'll try to remember and put them in next time xD
Original post by samb1234
Magnesium becomes limiting reagent (also your tags don't work)
Hasn't added the 4.
Original post by EricPiphany
How much Cu reacts? And you know the molar enthalpy change of the reaction already.
1 mol of Cu reacts?
so atm i have 9.676.7=m*4.18*delta T
Original post by thefatone
1 mol of Cu reacts?
so atm i have 9.676.7=m*4.18*delta T
so atm i have 9.676.7=m*4.18*delta T
Why 1 mol?
Original post by EricPiphany
Hasn't added the 4.
And added an a
Original post by EricPiphany
Why 1 mol?
actually since i have 50 g of Cu could i whap that in the formula?
Original post by thefatone
right so turns out when you edit tags in they don't work, beautiful. i'll try to remember and put them in next time xD
its the spelling that is the issue lol
Original post by samb1234
its the spelling that is the issue lol
oh
Original post by samb1234
And added an a
Good point
Original post by samb1234
its the spelling that is the issue lol
OK take this one for me, l wanna do some FP2.
Original post by samb1234
its the spelling that is the issue lol
help pls
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
Original post by thefatone
help pls
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
What did you get for part b?
Original post by thefatone
help pls
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
I'm doing something atm i'll help in 30 mins
Original post by EricPiphany
What did you get for part b?
..
Original post by thefatone
help pls
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
Original post by thefatone
help pls
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
i've done
Mol=Mass/mr
mass=mol*mr
=1*159.6 which is mr of CuSO4
then i did 9676.7/(159.6*4.18) and got 14.5K as change in temp
Find the number of moles of Mg, then times that by the enthalpy change to get energy change
Original post by EricPiphany
What did you get for part b?
for part b i got 2.43g which was the right answer
Original post by thefatone
for part b i got 2.43g which was the right answer
So now you are using 0.8g. (0.8/2.43)*46.3 will give you the new temp. increase.
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