These are the files that were within the attachment size limits for pdf. I think there was only a couple of files I couldnt upload so if you really need them let me know how I can share them.
These are the files that were within the attachment size limits for pdf. I think there was only a couple of files I couldnt upload so if you really need them let me know how I can share them.
Is the answer d) alizRin yellow R Because you are adding NaOH into ethanoic acid and NaOH is a strong base so the pH would go very high and by looking at the data booklet, the highest pH indication is D) alizarin yellow R
Is the answer d) alizRin yellow R Because you are adding NaOH into ethanoic acid and NaOH is a strong base so the pH would go very high and by looking at the data booklet, the highest pH indication is D) alizarin yellow R
I would disagree since we aren't looking at the end point but in fact the equivalence point. The equivalence point for the titration between a weak acid and strong base is 9 so from looking at the data booklet I would say the answer is C, thymol blue (base) since the pH range for thymol blue (base) is 8.0-9.6 and 9 is in that range (none of the other options have a suitable range). Hope that helps, @dinaa
I would disagree since we aren't looking at the end point but in fact the equivalence point. The equivalence point for the titration between a weak acid and strong base is 9 so from looking at the data booklet I would say the answer is C, thymol blue (base) since the pH range for thymol blue (base) is 8.0-9.6 and 9 is in that range (none of the other options have a suitable range). Hope that helps, @dinaa
Yep, I agree with you, i was looking at end point. Woopsies.
Is the answer d) alizRin yellow R Because you are adding NaOH into ethanoic acid and NaOH is a strong base so the pH would go very high and by looking at the data booklet, the highest pH indication is D) alizarin yellow R
What have you tried so far? Is it the whole of 18 or just some parts
I found the order wrt to [H+]
It is [Br-] that is confusing me.
Using experiment 1 and 3, the [H+] stays constant, [BrO3-] triples and [Br-] doubles. The rate is x6. I don't know how to link all this information together to get an order wrt [Br-].
Does anyone know what Kc actually is? I'm so confused because i thought it showed where the position of equilibrium was for a reaction but if that is the case then surely it would change with pressure/concentration because these move the position of equilibrium? Thanks
Kc actually stands for concentration constant ........questions related to Kc and Kp are usually calculations i mean i think i never solved a paper where they ask for the definition or something and in multiple choice questions its usually like they ask which factor effect the Kc or Kp and the answer always stays the same that is temperature ....anyways generally Kc and Kp are called equilibrium constant ...value of Kc is calculated using the equilibrium concentrations of the products and reactant.
Using experiment 1 and 3, the [H+] stays constant, [BrO3-] triples and [Br-] doubles. The rate is x6. I don't know how to link all this information together to get an order wrt [Br-].
Well we are told in the question that the reaction is first order wrt [BrO3-], so if we just tripled BrO3 what would we expect the rate to be? Therefore what factor is the bromine responsible for
so as it reduces chromium from +6 to +3 (orange to green) then the substance must be oxidised so it cannot be a ketone ( not c ) it reacts with HCN and KCN so must be a carbonyl but not ketone so has to be an aldehyde and as one mole of it reacts with two moles of HCN then there must be 2 aldehyde groups so answer is D ?
thank u so much i got it .....yes the answer is D ......yea I already knew that it would be an aldehyde but I was confused on how it reacted in terms of the structural formula ....thank u once again ...