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Find the value of the second derivative at a point, given the first derivative

If the first derivative = 2xy, then the value of the second derivative at the point (1,2) is?
a) 6
b) 8
c) 12
d) 16

I'm stumped, i don't know how to even start a question like this. Its new to me.
Can someone help me with this question? or at least give me some steps to follow?
Thanks
Reply 1
Original post by ksrw395
If the first derivative = 2xy, then the value of the second derivative at the point (1,2) is?
a) 6
b) 8
c) 12
d) 16

I'm stumped, i don't know how to even start a question like this. Its new to me.
Can someone help me with this question? or at least give me some steps to follow?
Thanks


You have f ' (x) = 2xy

Differentiate both sides with respect to x to get
f '' (x) = 2x(dy/dx) + 2y

Using the product rule. Now plug in the co-ords to get the gradient.
Reply 2
Original post by Zacken
You have f ' (x) = 2xy

Differentiate both sides with respect to x to get
f '' (x) = 2x(dy/dx) + 2y

Using the product rule. Now plug in the co-ords to get the gradient.


I did that and i got 12.
Thanks
Reply 3
Original post by ksrw395
I did that and i got 12.
Thanks


No problem.

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