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poisson distribution help

Accidents occur at a factory at an average rate of 5 per month. Find the probabilities that,
(b) there will be exactly 62 in a year.

so far I have figured out the new mean as 60 and have tried to work out
p(x=62) = (e^-60 x 60^62)/62!
I have typed this into the calculator and got error. Thanks in advance:smile:
Original post by Butterflyshy
Accidents occur at a factory at an average rate of 5 per month. Find the probabilities that,
(b) there will be exactly 62 in a year.

so far I have figured out the new mean as 60 and have tried to work out
p(x=62) = (e^-60 x 60^62)/62!
I have typed this into the calculator and got error. Thanks in advance:smile:


the value of lambda is scaled linearly for different time periods. in 12 months there will be on average 12 times as many accidents as in 1 month.

your method is right... the value is

0.04895671125 from the computer.

on your calculator it is better to do an approximation.... Normal with mean lambda & Variance lambda should work.
(edited 6 years ago)
you will need to apply a continuity correction as Poisson is for discrete data & Normal is for continuous.
Original post by the bear
you will need to apply a continuity correction as Poisson is for discrete data & Normal is for continuous.


thanks I'm getting the right answer now

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