Original post by I'm God
What steps did you take?
Spoiler
No idea what the answer is. I wrote it as 4sec4y*sqrt(sec^2(4y)-1) which gives what I said in the first post you substitute in x for sec4y.
Original post by RHI11
No idea what the answer is. I wrote it as 4sec4y*sqrt(sec^2(4y)-1) which gives what I said in the first post you substitute in x for sec4y.
Oh I see. I did it using quotient rule.
How do you know you are wrong?
Original post by I'm God
Oh I see. I did it using quotient rule.
How do you know you are wrong?
How do you know you are wrong?
b) show that dy/dx = k/x(sqrt(x^2 - 1))
My answer isn't in that form.
Original post by RHI11
My answer isn't in that form.
When you started, you did dx/dy, so did you flip the fraction to get dy/dx?
Original post by I'm God
When you started, you did dx/dy, so did you flip the fraction to get dy/dx?
Lol I'm an idiot thanks
Original post by RHI11
Lol I'm an idiot thanks
It's okay, I got it wrong, so now I need to figure out where
Does anyone know the answer to this for a or b ?
I differentiated part a. and got 1/4(sec4y)(tan4y) ?
I differentiated part a. and got 1/4(sec4y)(tan4y) ?
Original post by annonymous2394
Does anyone know the answer to this for a or b ?
I differentiated part a. and got 1/4(sec4y)(tan4y) ?
I differentiated part a. and got 1/4(sec4y)(tan4y) ?
x = (cos4y) ^ -1
Using chain rule, differentiate x w.r.t y
dx/dy = 4 * ((sec4y) ^ 2) * (sin4y)
using dy/dx = 1 / (dx/dy)
dy/dx = 1 / ( 4 * ((sec4y) ^ 2) * (sin4y) )
subs
dy/dx = (1/4) * (1 / ( (x)^2 * sqrt ( 1 - (1/x)^2 ) )
= k / (x * sqrt ( x^2 - 1) ), where k = 1/4
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