pleaseee help me with this physics question

figure seven: two people playing ice hockey.
player A: mass = 78kg velocity = +7.5 m/s
player B: mass = 91 kg velocity = -5.5 m/s

question:
immediately after the collision the two players move together to the right. calculate the velocity of the two players immediately after the collision.

Reply 1

user342

12

How much do you know about momentum

Reply 2

90 cent

16

m1u1 + m2u2 = m1v1 + m2v2

take 1 to be player A and 2 to be player B

for final momentum (v) their masses will be combined so add them .. (169v) should be on the r.h.side

585 + (-500.5) = 169v
and solve for v

Reply 3

meli77

OP

16

Original post by 90 cent

m1u1 + m2u2 = m1v1 + m2v2

take 1 to be player A and 2 to be player B

for final momentum (v) their masses will be combined so add them .. (169v) should be on the r.h.side

585 + (-500.5) = 169v
and solve for v

thank u so much

Reply 4

josieramona_

3

What paper is this on? Because I also did this but I'm struggling to find the mark scheme.Thank you :smile:

Reply 5

Lilysmithxoxo

14

Original post by meli77

thank u so much

So what would v be ???
And what equation was used

Reply 6

amydiannex

3

momentum= mass x velocity
And I got 0.5m/s for v but it doesn't sound right

Reply 7

Hafiz1212133

3

Original post by meli77

thank u so much

whats the answer?

Reply 8

avgy

3

Original post by meli77

figure seven: two people playing ice hockey.
player A: mass = 78kg velocity = +7.5 m/s
player B: mass = 91 kg velocity = -5.5 m/s

question:
immediately after the collision the two players move together to the right. calculate the velocity of the two players immediately after the collision.