need help with this physics ideal gases question!!
Issac physics G2.1
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
Original post by Meli5
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
thankyouu it helps
i didnt change into kelvin
Original post by anonymous12345.
Issac physics G2.1
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
What is the volume of a mole of gas at atmospheric pressure (1.01*10^5 Pa) and at 20 ∘C? Give your answer to two significant figures.
i dont do physics but acnt you just use PV = nRT
Original post by anonymous12345.
thankyouu it helps
i didnt change into kelvin
i didnt change into kelvin
np if you want you can upvote the answer
now how do you upvote the answer lmaoo
Original post by Meli5
pV = nRT
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
V = (nRT)/p
V = [1 x 8.31 x (20 + 273)] / 1.01*10^5
V = 0.0241 m^3 or 24107 cm^3
To 2 s.f = 0.0240 m^3 or 24000 cm^3
Hope this helps!
Original post by Meli5
np if you want you can upvote the answer
Original post by anonymous12345.
now how do you upvote the answer lmaoo
There is a like button just beneath it xd
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