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AS Physics Help

Hello, I'm stuck on these questions

Q1) What length of copper wire of diameter 0.38mm would be need to limit the current in it to 0.5A when connected to a 2V battery?

A=π(0.19×103)2A=\pi (0.19 \times10^{-3})^2

A=1.13×107A=1.13 \times 10^{-7}

V=IRV=IR

2=0.5R2=0.5R

R=4R=4

R=pLAR=\frac{pL}{A}

4=1.7×108×L1.13×1074=\frac{1.7\times10^{-8}\times L}{1.13\times 10^{-7}}

4(1.13×107)1.7×108=L,L=26.7\frac{4(1.13 \times10^{-7})}{1.7 \times10^{-8}}=L, L=26.7

Is that correct?

Q2)A 0.28mm diameter copper wire, 15.0m long, is connected to a 3.0V battery. Find its resistance and the current flowing.

A=π(0.14×103)2A=\pi(0.14 \times10^{-3})^2

A=6.18×108A=6.18 \times 10^{-8}

...What do I do next to answer the question?

Thanks a lot. :smile:
Duplicate question already answered in the other thread. :smile:

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