Trig identities

[1/cosθ] - [cosθ] apparently is equal to [1-cos^2θ/cosθ]

How?

(edited 13 years ago)

Awww man im so academic! I thought you were a teen maths prodidy or summat.

Gutted.

Do you know how to put fractions over a common denominator?

That's how.

For example,

\dfrac{1}{4} + 4 = \dfrac{1}{4} + \dfrac{4 \times 4}{4} = \dfrac{1 + 4^2}{4} = \dfrac{17}{4}

.

Except here you're working with a function rather than a number.

(edited 13 years ago)

Ignore the trigonometry.

Can you see why

\frac{1}{x} - x = \frac{1}{x} - \frac{x^2}{x} = \frac{1 - x^2}{x}

(edited 13 years ago)

Mr M

Ignore the trigonometry.

Can you see why

\frac{1}{x} - x = \frac{1}{x} - \frac{x^2}{x} = \frac{1 - x^2}{x}

Thank you! Perfect explanation. :smile:

How to revise for GCSE Maths: AQA explains what to do

What is an LLM and how could it benefit your career?

Powerful questions business students forget to ask their career advisers

Why I chose a law degree and what studying law was like