Cu(2+) ions reaction with OH(-) ions (observation)

I'm just wondering what observations to expect from carrying out a reaction of copper sulphate and sodium hydroxide.

Copper(II) ions + Sodium Hydroxide
Blue solution forms a blue precipitate and solution stays blue
Cu(2+) + 2OH(-) ==> Cu(OH)2 (s)

However I'm wondering if whether if excess NaOH is added whether the precipitate disappears?

I'm asking because I know this occurs with ammonia and in a sense its kind of the same reaction

NH3 + H2O ==> NH4(+) + OH(-)
Cu(2+) + 2OH(-) ==> Cu(OH)2(s)

Thanks in advance