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Cu(2+) ions reaction with OH(-) ions (observation) Watch

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    I'm just wondering what observations to expect from carrying out a reaction of copper sulphate and sodium hydroxide.

    Copper(II) ions + Sodium Hydroxide
    Blue solution forms a blue precipitate and solution stays blue
    Cu(2+) + 2OH(-) ==> Cu(OH)2 (s)

    However I'm wondering if whether if excess NaOH is added whether the precipitate disappears?

    I'm asking because I know this occurs with ammonia and in a sense its kind of the same reaction

    NH3 + H2O ==> NH4(+) + OH(-)
    Cu(2+) + 2OH(-) ==> Cu(OH)2(s)

    Thanks in advance
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    (Original post by Freerider101)
    I'm just wondering what observations to expect from carrying out a reaction of copper sulphate and sodium hydroxide.

    Copper(II) ions + Sodium Hydroxide
    Blue solution forms a blue precipitate and solution stays blue
    Cu(2+) + 2OH(-) ==> Cu(OH)2 (s)

    However I'm wondering if whether if excess NaOH is added whether the precipitate disappears?

    I'm asking because I know this occurs with ammonia and in a sense its kind of the same reaction

    NH3 + H2O ==> NH4(+) + OH(-)
    Cu(2+) + 2OH(-) ==> Cu(OH)2(s)

    Thanks in advance
    No, the ppt remains. Copper is not amphoteric and cannot form 'salts' with sodium hydroxide in the same way as aluminium.

    Ammonia dissolves the precipitate because a copper complex ion is formed, copper tetraammine (2+).
 
 
 
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