Thank you for your response, very helpful. I would agree with you here, since my numbers still come out as s = 8, i think its a ratio thing as in with the correct ratio of u and a the answer will always come out as s = 8, so surely they cannot mark mine wrong?
also what were the directiosn for u and a?
Many thanks...

was a=-0.125, i used s=8,u=2.25,a=?,t=32, then subbed in, im guessing this is completely wrong though.

Reply 47

username451352

11

Original post by Wezzler

was a=-0.125, i used s=8,u=2.25,a=?,t=32, then subbed in, im guessing this is completely wrong though.

a = 0.125, u = -1.75, v = 2.25, because it's initially at A and moving to B. Yours is correct for moving from B to A.

Reply 48

Tommo3

Original post by Bakes0011

a = 0.125, u = -1.75, v = 2.25, because it's initially at A and moving to B. Yours is correct for moving from B to A.

Yay, got the same, wonderful.

Reply 49

Polioz

OP

14

Original post by bear54

But there was no mention of time, the distance was 2.4
so the equation is V^2=u^2+2as

lool woops my bad i was trying to remmember the question off the top of my head and remembered the time I accidently worked out, yep I did the V^2=U^2+AS equation like you did.

Reply 50

Polioz

OP

14

what do you peeps think the grade boundaries will be like? I think this was a relatively easy paper?
60 or 61/72 for an A maybe? In my opinion this was the easiest test so far in m1 and the highest grade boundaries i have seen were 60ish...... some people in my college did find it hard though, so I am still hoping for LOW grade boundaries.. i need 90%+ ums in m1 as I floppped c2..

Reply 51

lawrence2jones

I really want to verify this, for question 4 I did it then realised I may have missed something crucial.

If the force P is horizontal, then did you need to split that into its component forms to find the side pointing up the slope to negate the (15g)sin20 pushing the block down the slope, then find the hypotenuse of the triangle with that side length for P?

Or was P just equal to (15g)sin20?

Cause I've spoken to about ten people (most of whom are pretty clever) who claim that P was simply (15g)sin20. But that doesn't seem to make sense?!?!?! Help!!!

Reply 52

bear54

Original post by lawrence2jones

I really want to verify this, for question 4 I did it then realised I may have missed something crucial.

If the force P is horizontal, then did you need to split that into its component forms to find the side pointing up the slope to negate the (15g)sin20 pushing the block down the slope, then find the hypotenuse of the triangle with that side length for P?

Or was P just equal to (15g)sin20?

Cause I've spoken to about ten people (most of whom are pretty clever) who claim that P was simply (15g)sin20. But that doesn't seem to make sense?!?!?! Help!!!

I think I did Pcos20=15gsin20, then divided by cos20 to get P

Reply 53

Ramya

Original post by lawrence2jones

I really want to verify this, for question 4 I did it then realised I may have missed something crucial.

If the force P is horizontal, then did you need to split that into its component forms to find the side pointing up the slope to negate the (15g)sin20 pushing the block down the slope, then find the hypotenuse of the triangle with that side length for P?

Or was P just equal to (15g)sin20?

Cause I've spoken to about ten people (most of whom are pretty clever) who claim that P was simply (15g)sin20. But that doesn't seem to make sense?!?!?! Help!!!

i got P as 15gsin20..i dunno if its right but im thinking that because the mass was in equilibrium the horizontal force P has to equal the horizontal component of the weight which is 15gsin20...hope its right lol

Reply 54

username451352

11

Original post by lawrence2jones

Cause I've spoken to about ten people (most of whom are pretty clever) who claim that P was simply (15g)sin20. But that doesn't seem to make sense?!?!?! Help!!!

It shouldn't make sense :wink:

It's wrong.

Reply 55

Polioz

OP

14

Original post by Bakes0011

It shouldn't make sense :wink:

It's wrong.

**** that means I labeled forces wrong aswell ... great 5 marks lost as i did P as parallel, dyu think I would get any method marks?.... here was me thinking i had 90%+ minimum -_-