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OCR MEI S3 20th January 2012

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Reply 20
Original post by OllieReynolds

Original post by OllieReynolds
Did everyone find the CV for the confidence interval in 2.(v) by using the t-distribution or the Normal distribution tables? Because n=20 (which is small, so i thought t-distribution would be correct), but there isn't a value for v=19 in the t-distribution table... :s-smilie:


I think I used the normal distribution tables there, in the question I think it said that the standard deviation was assumed to be 15 (?) so as it wasn't estimated from sample data I used the normal tables
Original post by B Jack
I think I used the normal distribution tables there, in the question I think it said that the standard deviation was assumed to be 15 (?) so as it wasn't estimated from sample data I used the normal tables


Arghhh, I did that at first, but throughout the rest of the paper it was bugging me until i changed it to use the t-distribution at the very end and crossed out the normal distribution :-/ Cheers though!
Reply 22
Original post by B Jack
The normal distribution question where you had to find the probablity that two small bags differed by less than 25 grams, were you meant to find P(-25<S1-S2<25)? I don't remember seeing a question along these lines in any of the past papers so it confused me a little :s-smilie: Generally though I thought the paper was ok, anyone remember any of the test statistics they got for any of the questions?


I think that's right yeah. I'm kicking myself though - I believe I wrote P(S1-S2<25) or something like that...

Can't really remember... For Wilcoxon I think I got W=6, which was larger than critical value, which was 5.

Does anyone remember how many estimated parameters you took away for the chi-squared one?
Reply 23
Original post by Beth1234
I think that's right yeah. I'm kicking myself though - I believe I wrote P(S1-S2<25) or something like that...

Can't really remember... For Wilcoxon I think I got W=6, which was larger than critical value, which was 5.

Does anyone remember how many estimated parameters you took away for the chi-squared one?


I think I ended up with v=2, because you had 5 clases, and you had to merge two of them as one of the expected frequences was less than 5, giving 4 classes; and the mean was used from the observed frequencies to calculate the expected frquencies, but nothing was mentioned about standard deviations or variance, so I ended up with v=4-1-1=2.
I remember the critical value being 5, but I think I got something like W=11 :s-smilie:
I can't remember the test statistics for other tests, but I think the t distribution question rejected the null hypothesis and the chi-squared one accepted the null hypothesis, though marginally.
Reply 24
Original post by B Jack
I think I ended up with v=2, because you had 5 clases, and you had to merge two of them as one of the expected frequences was less than 5, giving 4 classes; and the mean was used from the observed frequencies to calculate the expected frquencies, but nothing was mentioned about standard deviations or variance, so I ended up with v=4-1-1=2.
I remember the critical value being 5, but I think I got something like W=11 :s-smilie:
I can't remember the test statistics for other tests, but I think the t distribution question rejected the null hypothesis and the chi-squared one accepted the null hypothesis, though marginally.


Ah good, I ended up with v=2 too :smile:

Not so good with the W value... I got W- as my smaller one, did you? :s-smilie:
Reply 25
Original post by Beth1234
Ah good, I ended up with v=2 too :smile:

Not so good with the W value... I got W- as my smaller one, did you? :s-smilie:


W- was my smaller one too, from what I remember I think I had 3 ranks contributing to W- but I cannot remember what those ranks were :s-smilie:
(edited 12 years ago)
Original post by B Jack
I think I ended up with v=2, because you had 5 clases, and you had to merge two of them as one of the expected frequences was less than 5, giving 4 classes; and the mean was used from the observed frequencies to calculate the expected frquencies, but nothing was mentioned about standard deviations or variance, so I ended up with v=4-1-1=2.
I remember the critical value being 5, but I think I got something like W=11 :s-smilie:
I can't remember the test statistics for other tests, but I think the t distribution question rejected the null hypothesis and the chi-squared one accepted the null hypothesis, though marginally.


Yes i agree with you here and i felt quite confident about these questions
Reply 27
Original post by OllieReynolds
Yes i agree with you here and i felt quite confident about these questions


You mean you got W=11 as well?

Well, here goes a lot of marks... :s-smilie:
Original post by Beth1234
You mean you got W=11 as well?

Well, here goes a lot of marks... :s-smilie:


It was something like that... because n = 8, so 0.5n(n+1) = 36 and i remember both W's were double digits. The other was around 25 so W was about 11. Either way it was above the critical value, so H1 was accepted
Reply 29
Original post by OllieReynolds
It was something like that... because n = 8, so 0.5n(n+1) = 36 and i remember both W's were double digits. The other was around 25 so W was about 11. Either way it was above the critical value, so H1 was accepted


Ho hum. I got W- as 6 and W+ as 30... dear God, I hope I get some marks after that, for reaching the correct conclusion... :cry:
Reply 30
I randomly just remembered in the last two parts of question 4 that the variance i got with the central limit theorem was 0.28125 (9/32) does this ring any bells?
Reply 31
Original post by B Jack
I randomly just remembered in the last two parts of question 4 that the variance i got with the central limit theorem was 0.28125 (9/32) does this ring any bells?


No :tongue: But I truly cannot remember that question if my life depended on it, so it may well have been that.

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