sin (x) = 1/(root 3) .. =0.62. WHAT?

Hello, hey.

I was just wonderign how that was possible. 1/(root 3) is not in the special triangles, the inverse on calculators give 35.26... there are a lot of questions like this, perhaps you could shed some light on this one for me.

THANKS


btw, the question is . Find a solution,where 0 < x < pi/2 (90?)
Do not use a calculator if the answer ccan be found from special triangles.


Also, 0< tita < 2pi
cos tita = -1/3
tita = 1.9, 4.4
where are these decimals coming from?

Hello, hey.

I was just wonderign how that was possible. 1/(root 3) is not in the special triangles, the inverse on calculators give 35.26... there are a lot of questions like this, perhaps you could shed some light on this one for me.

THANKS


btw, the question is . Find a solution,where 0 < x < pi/2 (90?)
Do not use a calculator if the answer ccan be found from special triangles.


Also, 0< tita < 2pi
cos tita = -1/3
tita = 1.9, 4.4
where are these decimals coming from?

For $\dfrac{1}{\sqrt{3}}$, draw an equilateral triangle of side length 2. Then 'chop' it in half from any corner to the middle of the opposite side. Proceed to work out sides and angles and how they relate.

For $\dfrac{1}{\sqrt{3}}$, draw an equilateral triangle of side length 2. Then 'chop' it in half from any corner to the middle of the opposite side. Proceed to work out sides and angles and how they relate.

For the second thing, I've got to start by saying it's theta, not tita.

And I'm pretty certain they're using a calculator there. What's wrong with decimals?

That doesn't help with sin theta = 1/sqrt(3).

The OP's first post isn't clear, she needs to write the complete question.

$\theta$ is called 'theta' not 'tita'.

You haven't given the complete question, $0 < x < \dfrac{\pi}2$ is just the range, where is the equation for which we need to find the solutions?

For $\dfrac{1}{\sqrt{3}}$, draw an equilateral triangle of side length 2. Then 'chop' it in half from any corner to the middle of the opposite side. Proceed to work out sides and angles and how they relate.

For the second thing, I've got to start by saying it's theta, not tita.

And I'm pretty certain they're using a calculator there. What's wrong with decimals?

the equation is this :

sinx x = 1/(root 3)


(i don't know how to do the square root sign but it's a fraction under one)

Sorry about the theta >< I've never seen it written down before , but now I have

the equation is this :

sinx x = 1/(root 3)


(i don't know how to do the square root sign but it's a fraction under one)

Sorry about the theta >< I've never seen it written down before , but now I have

Oh sorry I didn't actually read the title while I was writing that, just the actual post where sine wasn't mentioned

Yeah then OP, use a calculator.

but what do I type into the calculator? o.o

inverse sine gives me 35.5 something...normal sin gives me 0.01007...

How does that eventually work out to be solved as 0.62?

I've tried to do that earlier, but I can't seem to make it work with the triangles.

nothing is wrong with decimals. I just don't understand how to get it as my answer

By the way, are you sure the question asks you to find the value of $x \ ?$

It may be asking you to find $cosx \ or \ tanx$

There is no more information from the question. and I do not think so. this is part e) of the question. part a) was sin x =1/2 and the answer for that was pi/6 which i understand and used the special triangle for it.

I'm not sure how i can use the calculator to get 0.62

thanks

Hello, hey.

I was just wonderign how that was possible. 1/(root 3) is not in the special triangles, the inverse on calculators give 35.26... there are a lot of questions like this, perhaps you could shed some light on this one for me.

THANKS


btw, the question is . Find a solution,where 0 < x < pi/2 (90?)
Do not use a calculator if the answer ccan be found from special triangles.


Also, 0< tita < 2pi
cos tita = -1/3
tita = 1.9, 4.4
where are these decimals coming from?

There is no more information from the question. and I do not think so. this is part e) of the question. part a) was sin x =1/2 and the answer for that was pi/6 which i understand and used the special triangle for it.

I'm not sure how i can use the calculator to get 0.62

thanks

You need to use the inverse sin.

If your calc is in degrees then you will get 35deg. if it is radian then you will get 0.62rad.

Just because 1 over root 3 is involved in the question doesn't mean it in going to be a non calculator thing.

If you read the question carefully it is asking you for where solutions 0 < x < pi/2
So you can work it out in degree like you have done which came out to 35.26 right? HOWEVER it says it has to be in radians hence pi/2. To convert degrees in radians you have to mulitply 35.26 by PI (3.14....) then divide by 180.

So 35.26 x Pi / 180 = Answer you were looking for