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FP1 - Finding arguments in terms of pi

Hey guys. I'm currently stuck on the argument and modulus form. I do understand the modulus part, but I have absolutely no idea where you get arguments in terms of pie from.

Say:

arg z = arctan (1/ - square root of three) = -pie/6
Can you please explain to me where this -pie/6 came from? I would be eternally grateful! Thanks!!
Reply 1
The pi/6 is just the angle in radians.


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Reply 2
Original post by Matt_dragon
Hey guys. I'm currently stuck on the argument and modulus form. I do understand the modulus part, but I have absolutely no idea where you get arguments in terms of pie from.

Say:

arg z = arctan (1/ - square root of three) = -pie/6
Can you please explain to me where this -pie/6 came from? I would be eternally grateful! Thanks!!


tanπ6=33tan \frac{\pi}{6}=\frac{\sqrt{3}}{3}

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