The Student Room Group

Energy related to position dependant force

The position-dependent force acting on an object is given by f(x)= -kx^2
k is a constant
at x=x1 m, the force is known to point in the negative x direction and have a
magnitude of F1 N

(a) Find the expression for potential energy U(x) associated with this force as a
function of x, assuming we assign a reference value of U2 joules at x = x2 m for the
potential energy

b) Find the position of the equilibrium of the object under the action of this force

x1=0.5, f1=50, u2=6, x2=1.5


i started by saying that
f(x1)= -k/4... 50= -k/4 therefore k= -200
u(x)= integral(f(x)) u(x)= -2kx+c 6= -2(-200)(1.5)+c c= -594
Have i started along the right lines? Any advice is welcome, and will be much appreciated.
(edited 10 years ago)

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