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Help with C2 Trigonometric functions please

ImageUploadedByStudent Room1397315146.262853.jpg

It is question 3. So far I have done this, but I do not know what to do now.

ImageUploadedByStudent Room1397315193.576541.jpg

Thanks


Posted from TSR Mobile
I would suggest drawing a graph of y = tanx from -pi to pi. You can then draw two lines on it, y = root(1/3) and y = -root(1/3). Use the periodic nature of tan to then find the intersections. :smile:

Or, you could just use the fact that tan(x + pi) = tan(x) to find the other solutions in the interval.
(edited 10 years ago)
Reply 2
Original post by Efemena15
ImageUploadedByStudent Room1397315146.262853.jpg

It is question 3. So far I have done this, but I do not know what to do now.

ImageUploadedByStudent Room1397315193.576541.jpg

Thanks


Posted from TSR Mobile


Good so far.

Just add pi to -pi/6 to get 5pi/6

Also subtract pi from pi/6 to get -5pi/6.
Reply 3
Just add/subtract pipi (because of symmetry) to the principle values obtained for tan
(edited 10 years ago)
Reply 4
Original post by BabyMaths
Good so far.

Just add pi to -pi/6 to get 5pi/6

Also subtract pi from pi/6 to get -5pi/6.


Original post by Inevitable
Just add/subtract pipi (because of symmetry) to the principle values obtained for tan


Ok, thanks guys, but why do I add/take away pi. I'm trying to practice using the CAST diagram, so if you could explain it like that, that would be helpful.

Thanks
Reply 5
Original post by Efemena15
Ok, thanks guys, but why do I add/take away pi. I'm trying to practice using the CAST diagram, so if you could explain it like that, that would be helpful.

Thanks


because tan(x)=tan(x+kπ)\tan(x)=\tan(x+k\pi) where k is any integer.

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