The Student Room Group

AQA D1 June 2014 Unofficial Mark Scheme

Here is an unofficial mark scheme for the D1 paper we sat today. I would appreciate it if people could contribute their answers, and if any of mine are wrong, please tell me! Marks are in emboldened, underlined brackets, like so [x]. Corrected answers that are still being debated are simply underlined, as so x.

The exam paper is attached to the bottom of this post; thanks to maggiehodgson for it!

Unparseable latex formula:

[br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Adjacency matrix linking} A-3; B-1,2,3; C-3,4,5; D-2,4; E-2,4 \hfill \textbf{\underline{[2]}} \\[br]\item[br]\begin{enumerate}[br]\item \text{Matching} A3, B1, C5, D2, E4 \hfill \textbf{\underline{[3]}} \\[br]\item \text{Matching} A3, B1, C5, D4, E2 \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{1}[br]\item [br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{MST:} EF, EG, GD, FI, IS, GH \hfill \textbf{\underline{[5]}} \\[br]\item \text{Length} = 485 \hfill \textbf{\underline{[1]}} \\[br]\item \text{Draw the MST} \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Last two edges for Prim's} FI, IS \hfill \textbf{\underline{[1]}} \\[br]\item \text{Last two edges for Kruskal's} FI, GH \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{2}[br]\item [br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Box 61 at K} \hfill \textbf{\underline{[6]}} \\[br]\item A-B-E-I-K \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\item \text{Length via D} = 63 \hfill \textbf{\underline{[1]}} \\[br]\item \text{Length without I} = 64, A-B-F-J-K \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{3}[br]\item [br]\begin{enumerate}[br]\item \text{Optimal length} = 94.5 \text{minutes} \hfill \textbf{\underline{[5]}} \\[br]\item[br]\begin{enumerate}[br]\item \text{Pass F twice} \hfill \textbf{\underline{[1]}} \\[br]\item \text{Pass D three times} \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Shortest for mayor} = 85.5 \text{minutes} \hfill \textbf{\underline{[2]}} \\[br]\item \text{Start at E or G} \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{4}[br]\item [br]\begin{enumerate}[br]\item \text{Draw graph, indicating FR} \hfill \textbf{\underline{[5]}} \\[br]\item[br]\begin{enumerate}[br]\item P = 30 (9, 3) \hfill \textbf{\underline{[2]}} \\[br]\item P = 29.6 (6.4, 5.6) \hfill \textbf{\underline{[2]}} \\[br]\item P = -15 (9, 3) \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{5}[br]\item [br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Best upper bound} = 30 \hfill \textbf{\underline{[1]}} \\[br]\item \text{Best lower bound} = 20 \hfill \textbf{\underline{[1]}} \\[br]\end{enumerate}[br]\item[br]\begin{enumerate}[br]\item M-L-N \text{shorter} \hfill \textbf{\underline{[1]}} \\[br]\item \text{Upper bound} = 932 \hfill \textbf{\underline{[1]}} \\[br]\item M-L-N-L-B-L-E-L-M \hfill \textbf{\underline{[2]}} \\[br]\item \text{Upper bound} = 796 \hfill \textbf{\underline{[4]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{6}[br]\item 2x + 5y + 5z \leq 120 \\ x + 2y + 2z \leq 30 \\ 2x + 3y + 4z \leq 60 \\ x \textgreater y + z \\ y \geq z \\ 17y \geq 3x + 3z \hfill \textbf{\underline{[8]}} \\[br]\end{enumerate}[br]



Unparseable latex formula:

[br]\begin{enumerate}[br]\setcounter{enumi}{7}[br]\item [br]\begin{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Even number of odd vertices only when x is odd} \hfill \textbf{\underline{[2]}} \\[br]\item x=1, \text{draw graph} \hfill \textbf{\underline{[3]}} \\[br]\end{enumerate}[br]\item[br]\begin{enumerate}[br]\item \text{Minimum degree} = 0, \text{Maximum degree} = 9 \hfill \textbf{\underline{[2]}} \\[br]\item \text{Can't have one vertex with degree 9 and one with 0} \therefore \text{9 possible degrees, 10 vertices} \hfill \textbf{\underline{[2]}} \\[br]\end{enumerate}[br]\end{enumerate}[br]\end{enumerate}[br]

(edited 9 years ago)

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I should have 68/75 (being optimistic) if this is correct! (which would be an amazing improvement on my 60 UMS last year) Thanks so much for doing it :smile: I'm super worried the grade boundaries will be high though, last year was tough!
(edited 9 years ago)
For 5bi) I got 24.8 (with the max coord (6.4,5.6). I may have dropped a mark on the formulation of equations and my explanation was different for 8bii but otherwise pretty similar.
Typo question 7 inequality 2, should be 2z not 2 lots of 2y?

Also q6 iv, sure it said nearest neighbour, not lower bound?

Think i agree with rest of answers
(edited 9 years ago)
Reply 4
6.b iv. I don't remember them asking for a lower bound, I only remember asking them by using nearest neighbour, find another upper bound. I don't think there was any lower bound questions.

Edit: The only lower bound question was 6.a.ii Where it asks you for the best lower bound. But in no question did it ask you to find a lower bound.

Posted from TSR Mobile
(edited 9 years ago)
Reply 5
I challenge your 8b. i. Minimum degree of 0. I thought minimum would be 1 and Max is 9

Posted from TSR Mobile
for Q5biii I got a positive value for P, I think my x value was 1.
Reply 7
Original post by Doomlar
.


Why would the maximum value be -15 and not 5.6?
Original post by Red Fox
Why would the maximum value be -15 and not 5.6?



If you're talking about the last function on the linear programming, it said the minimum value of the function
Here the questions

I am as bad at uploading as I am at Decision Maths. I did nearest neighbour instead of Prim's and I knew there was something wrong when I was doing it. Penny dropped as I walked out of the exam room. Also didn't even understand the final question.

My prediction for this is that everyone gets A or A* and I get a D if I'm lucky.

Good job I only do maths as a hobby. Knitting sawdust classes here I come.

All the best to all TSR maths students. I've loved reading the posts and I have learnt a lot but sadly not enough.

Happy summer and great futures to you all.
(edited 9 years ago)
Original post by Red Fox
Why would the maximum value be -15 and not 5.6?

I believe the question asked for a minimum value
Reply 11
Original post by maggiehodgson
Here the questions


You missed question 1.

Posted from TSR Mobile
Reply 12
Original post by HesitantCicada
I believe the question asked for a minimum value


Yeah it did.

Posted from TSR Mobile
Original post by tdarren
I challenge your 8b. i. Minimum degree of 0. I thought minimum would be 1 and Max is 9

Posted from TSR Mobile


I agree with this! (Because it wanted a simple graph and simple means all vertices are connected in some way right?)
(edited 9 years ago)
Original post by tdarren
6.b iv. I don't remember them asking for a lower bound, I only remember asking them by using nearest neighbour, find another upper bound. I don't think there was any lower bound questions.

Posted from TSR Mobile


[edit] Ignore me, you were right, just looked at the above posted questions and it all came flooding back haha :smile:
(edited 9 years ago)
Original post by FeelsToWaltz
for Q5biii I got a positive value for P, I think my x value was 1.


I got -15, same as the answers, but it didn't feel right. It was an annoying one because I didn't revise objective lines with a negative gradient :frown:
Reply 16
Original post by itsalmostbeth
[edit] Ignore me, you were right, just looked at the above posted questions and it all came flooding back haha :smile:


Do you know the question number? I know there is a lower bound question for 6.a ii. But I don't remember deleting C at all in any question.

Edit: You edited.


Posted from TSR Mobile
No lower bounds, but 796 was still the answer (or at least the one I got).
Also I'm not sure what people are questioning about "P=-15" - it wanted the minimum value of the objective/profit line thing, not the minimum value of x.
Original post by itsalmostbeth
I got -15, same as the answers, but it didn't feel right. It was an annoying one because I didn't revise objective lines with a negative gradient :frown:

I got -15 :biggrin:
Reply 19
It was a good test for me. No time issues like the other maths tests (C3 and C4).
(edited 9 years ago)

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