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A level C1 Polynomial question (factor theorem)

Struggling to do 12(c) on the attached question it makes no sense to me I have tried to make it = 0 and use trial and error with factor theorem but haven't go an answer. Btw k = 12.

Can somebody help me
Reply 1
Original post by Sayless
Struggling to do 12(c) on the attached question it makes no sense to me I have tried to make it = 0 and use trial and error with factor theorem but haven't go an answer. Btw k = 12.

Can somebody help me


as everybody disappeared this afternoon I will try to help you.

The Factor theorem states that if (x-2) is a factor of a polynomial f(x), then f(2) must equal zero.

So if you substitute x=2 into the polynomial you would expect to get zero,

see if this helps ...
Reply 2
Original post by TeeEm
as everybody disappeared this afternoon I will try to help you.

The Factor theorem states that if (x-2) is a factor of a polynomial f(x), then f(2) must equal zero.

So if you substitute x=2 into the polynomial you would expect to get zero,

see if this helps ...


I have done that part, its just 12(c) which I am stuck on
Reply 3
Original post by Sayless
I have done that part, its just 12(c) which I am stuck on


sorry I was busy and I did not look properly.

for (c) use the fact that a^6 = (a^2)^3 and use part (b)
(edited 9 years ago)
Reply 4
part (b) I meant
Reply 5
Original post by TeeEm
sorry I was busy and I did not look properly.

for (c) use the fact that a^6 = (a^2)^3 and use part (b)


thanks i'll try that
Reply 6
Original post by TeeEm
sorry I was busy and I did not look properly.

for (c) use the fact that a^6 = (a^2)^3 and use part (b)


doesn't work
Reply 7
Original post by Sayless
doesn't work


let y2=x in the second equation

Then say the y6=(y2)3

does this help?
I'd start by subtracting 64 from both sides. From there, it is possible to factorise and solve.
Reply 9
Original post by TeeEm
let y2=x in the second equation

Then say the y6=(y2)3

does this help?


yes i understand now but how did you work out that y^2 = x
Reply 10
Original post by Sayless
yes i understand now but how did you work out that y^2 = x


it should be obvious that the coefficients of the two equations are the same (numbers in front of letters)

then x^3 goes to y^6
then x^2 goes to y^4
then x^1 goes to y^2

hope it makes sense
Reply 11
Original post by TeeEm
it should be obvious that the coefficients of the two equations are the same (numbers in front of letters)

then x^3 goes to y^6
then x^2 goes to y^4
then x^1 goes to y^2

hope it makes sense


yes it does thanks for your help

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