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###### Send me your maths questions!

watch this thread

1 month ago

A level student looking to use my skills to give back to the community (and have something nice to say in my ps😅). If your a student in yr10-yr12 struggling with any maths problems (preferably pure cuz I hate stats lol) send them to me and I’ll try to solve and explain them to you. Emphasis on “try” cuz I can’t guarantee that I know the answer lmao.

Reply 1

1 month ago

I'll offer a (fairly) simple question as a warm up...

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

Original post by Arnold Rimmer

I'll offer a (fairly) simple question as a warm up...

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

lol i think they just wanted to help students with hw or revision, not do math questions for fun

Original post by million.

lol i think they just wanted to help students with hw or revision, not do math questions for fun

lol i think they just wanted to help students with hw or revision, not do math questions for fun

No I actually like doing maths for fun so send me these as well😅

Original post by Arnold Rimmer

I'll offer a (fairly) simple question as a warm up...

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

Prove the angle at the centre theorem (any angle at the centre is twice that of the circumference). If you want an extra challenge, you can't say the centre angle is 180 - 2x (this is a bit of a hint as well).

Done it, took me like 30 seconds to get the answer but proof writing is longer than solving the acc question lmao🤣. Nice question tho gave me some GCSE nostalgia.

Original post by Dumbo786

Hi can you workout the product of 99x1089 using addition and subtraction calculations only please

Looking at it now

Original post by Tbc_losis

Alr I think I’ve got (questions kinda ambiguous so I’ll do my best):

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

Given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

This can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

Hope this helps!

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

Given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

This can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

Hope this helps!

9^2 factor?

But the simple way would be 108900-1089 = ...

Original post by mqb2766

9^2 factor?

But the simple way would be 108900-1089 = ...

9^2 factor?

But the simple way would be 108900-1089 = ...

Damn￼ ur right, how’d u solve it like that😅

Original post by tbc_losis

alr i think i’ve got (questions kinda ambiguous so i’ll do my best):

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

this can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

hope this helps!

alr i think i’ve got (questions kinda ambiguous so i’ll do my best):

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

this can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

hope this helps!

nevermind dont listen to me i butchered that question what the hell??!!

Original post by Tbc_losis

Alr I think I’ve got (questions kinda ambiguous so I’ll do my best):

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

Given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

This can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

Hope this helps!

Not sure if this is what was intended but you can take out the factor of 9 from both sides with some mental maths to get 9(11x121)

Given that 121 is just 11^2 you can take out another factor of 11 to get 99(1x11)

This can then be written as 99x11 which is just 99 + 99 + 99… 11 times.

Would be very tedious to do all the addition but you’d eventually get the answer your looking for

Hope this helps!

Please note the maths forum rules forbid posters from solving questions - we only give hints. Please stop doing questions for people.

Reply 14

1 month ago

Original post by Tbc_losis

Damn￼ ur right, how’d u solve it like that😅

Assuming you know now but 99 = 100 - 1

Reply 15

1 month ago

Original post by Tbc_losis

Done it, took me like 30 seconds to get the answer but proof writing is longer than solving the acc question lmao🤣. Nice question tho gave me some GCSE nostalgia.

Assuming you used this proof: An exterior angle of a triangle is equal to the sum of its two opposite non-adjacent interior angles.

Reply 16

1 month ago

Hope you like mechanics

a smooth ring is threaded on a light inextensible string. the ends of the string are attached to a horizontal ceiling, and make angles of 30 and 60 degrees with the ceiling respectively. The ring is held in equilibrium by a horizontal force of magnitude 8N. Whats the tension

a smooth ring is threaded on a light inextensible string. the ends of the string are attached to a horizontal ceiling, and make angles of 30 and 60 degrees with the ceiling respectively. The ring is held in equilibrium by a horizontal force of magnitude 8N. Whats the tension

Original post by egghead3939

Hope you like mechanics

a smooth ring is threaded on a light inextensible string. the ends of the string are attached to a horizontal ceiling, and make angles of 30 and 60 degrees with the ceiling respectively. The ring is held in equilibrium by a horizontal force of magnitude 8N. Whats the tension

a smooth ring is threaded on a light inextensible string. the ends of the string are attached to a horizontal ceiling, and make angles of 30 and 60 degrees with the ceiling respectively. The ring is held in equilibrium by a horizontal force of magnitude 8N. Whats the tension

Dont spam the same question pls.

Original post by Arnold Rimmer

Assuming you used this proof: An exterior angle of a triangle is equal to the sum of its two opposite non-adjacent interior angles.

Assuming you used this proof: An exterior angle of a triangle is equal to the sum of its two opposite non-adjacent interior angles.

I￼ actually didn’t I just split triangle into two with a radius

Reply 19

1 month ago

Original post by username6524289

Assuming you used this proof: An exterior angle of a triangle is equal to the sum of its two opposite non-adjacent interior angles.

Elegant proof.

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