The Student Room Group

As Chemistry help molarity

Determine the molarity of the individual ions in the following:
2M Al(OH)3 4M Na2 SO4 1/2M Ca3 (PO4)2 0.5M Al2(SO4)3
3M K2 SO4
if you could explain how to work any one of these then I would appreciate it a lot thanks.
Sorry you've not had any responses about this. :frown: Are you sure you’ve posted in the right place? Posting in the specific Study Help forum should help get responses. :redface:

I'm going to quote in Tank Girl now so she can move your thread to the right place if it's needed. :h: :yy:

Spoiler

Original post by zak7399
Determine the molarity of the individual ions in the following:
2M Al(OH)3 4M Na2 SO4 1/2M Ca3 (PO4)2 0.5M Al2(SO4)3
3M K2 SO4
if you could explain how to work any one of these then I would appreciate it a lot thanks.


Ionic compounds dissociate 100% in solution, so if there are two ions in the formula unit then the concentration of ions in solution will be double that of the compound itself.

eg:

CuCl2 -- (aq) --> Cu2+(aq) + 2Cl-(aq)

If the copper(II) chloride concentration is 1M then the chloride concentration is 2M ...
Reply 3
Original post by charco
Ionic compounds dissociate 100% in solution, so if there are two ions in the formula unit then the concentration of ions in solution will be double that of the compound itself.

eg:

CuCl2 -- (aq) --> Cu2+(aq) + 2Cl-(aq)

If the copper(II) chloride concentration is 1M then the chloride concentration is 2M ...


Thanks:smile:

Quick Reply

Latest