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    I'm stuck!
    x/2x-1 +2/x+2=1

    I did this:
    x(x+2)/(2x-1)(x+2) + 2(2x-1)/(2x-1)(x+2)=1
    x^2+6x-2=1
    x^2+6x-3=0
    Now i don't know what to do. Let me know what I need to do please!
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    (Original post by isabel12144)
    I'm stuck!
    x/2x-1 +2/x+2=1

    I did this:
    x(x+2)/(2x-1)(x+2) + 2(2x-1)/(2x-1)(x+2)=1
    x^2+6x-2=1
    x^2+6x-3=0
    Now i don't know what to do. Let me know what I need to do please!
    Can you show how you worked out the quadratic equation from this
    x(x+2)/(2x-1)(x+2) + 2(2x-1)/(2x-1)(x+2)=1.

    I got a different quadratic equation.
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    Don't you know how to solve a quadratic?

    The simplification is incorrect regardless.
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    (Original post by MathQ123)
    Can you show how you worked out the quadratic equation from this
    x(x+2)/(2x-1)(x+2) + 2(2x-1)/(2x-1)(x+2)=1.

    I got a different quadratic equation.
    x^2+2x/2x^2+3x-2 + 4x-2/2x^2+3x-2=1
    x^2+6x-2=1
    x^2+6x-3=0
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    (Original post by isabel12144)
    I'm stuck!
    x/2x-1 +2/x+2=1

    I did this:
    x(x+2)/(2x-1)(x+2) + 2(2x-1)/(2x-1)(x+2)=1
    x^2+6x-2=1
    x^2+6x-3=0
    Now i don't know what to do. Let me know what I need to do please!
    I assume you mean \frac{x(x+2)}{(2x-1)(x+2)} + \frac{2(2x-1)}{(2x-1)(x+2)}=1?
    In which case I'm not sure how you got that simplification. I get: \frac{x(x+2)+2(2x-1)}{(2x-1)(x+2)}=1
    x(x+2)+2(2x-1)=(2x-1)(x+2)

    From there expand the brackets and rearrange so the equation is equal to 0. Then solve like any other quadratic.
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    (Original post by Andy98)
    I assume you mean \frac{x(x+2)}{(2x-1)(x+2)} + \frac{2(2x-1)}{(2x-1)(x+2)}=1?
    In which case I'm not sure how you got that simplification. I get: \frac{x(x+2)+2(2x-1)}{(2x-1)(x+2)}=1
    x(x+2)+2(2x-1)=(2x-1)(x+2)

    From there expand the brackets and rearrange so the equation is equal to 0. Then solve like any other quadratic.
    Thanks!
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    (Original post by isabel12144)
    Thanks!
    You got it?
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    (Original post by Andy98)
    You got it?
    I think so.
    X^2-3x=0
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    (Original post by isabel12144)
    I think so.
    X^2-3x=0
    So x is 0 or 3?
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    (Original post by isabel12144)
    So x is 0 or 3?
    If you've simplified correctly (I haven't checked your algebra!) those are the correct solutions to the quadratic equation you posted in your previous post
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    (Original post by isabel12144)
    I think so.
    X^2-3x=0
    That is right
 
 
 
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