Hey there! Sign in to join this conversationNew here? Join for free
x Turn on thread page Beta

Need help with this Physics Electricity question! watch

    • Thread Starter


    I'm really struggling with the last part

    break the complicated network of resistors down into managable chunks that you know how to deal with by using the rules for combining resistances in series and in parallel to replace 2 or more resistors with one equivalent resistor.

    the rule for series resistances is Requiv=R1+R2...

    the rule for parallel resistances is 1/Requiv=(1/R1)+(1/R2)...

    step 1: you have one resistor Z in series with the network consisting of WXY
    if Z is 3 ohms then the resistance of the network WXY must be 2 ohms

    step 2: combined resistance of the series resistors W and X in the upper branch = 3+3 ohms = 6 ohms

    step 3: combined resistance of the resistor Y in parallel with the equivalent value for W and X... which must be equal to 2 (step 1)

    1/2=(1/3) + (1/6)
    1/2=(2/6) + (1/6)
    1/2=3/6 which is true

    might be helpful to redraw the circuit at each stage of simplification until you get the hang of it.
Submit reply
Turn on thread page Beta
Updated: November 8, 2015
Do you agree with the proposed ban on plastic straws and cotton buds?

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Write a reply...
Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.