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Bond enthalpies

cjm1998

Is anyone able to solve this please? Thanks :smile:

Giventhe following information:

C(s) à C(g), DH = +715 kJmol^-1Cl₂(g) à 2Cl(g), DH = +242 kJmol^-1C(s) + 2Cl₂(g) à CCl₄(g), DH = -135.5 kJmol^-1

Calculate the average bond dissociation enthalpy ofa C-Cl bond.

Reply 1

charco

Study Forum Helper

Original post by cjm1998

Is anyone able to solve this please? Thanks :smile:

Giventhe following information:

C(s) à C(g), DH = +715 kJmol^-1Cl₂(g) à 2Cl(g), DH = +242 kJmol^-1C(s) + 2Cl₂(g) à CCl₄(g), DH = -135.5 kJmol^-1

Calculate the average bond dissociation enthalpy ofa C-Cl bond.

You should write the equation for dissociation of a carbon tetrachloride molecule (giving C + 4Cl) and then construct this using the equations that you are given...

Do the same operation for the enthalpy as you manipulate the equations and this will lead you to the enthalpy change for CCl₄ --> C + 4Cl

Finally divide by four to get the average for each C-Cl bond.