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Applying y=mx+x to Gibbs free energy equation

I meant y=mx+c in the title

Can someone explain to me how to apply the equation of a straight line to the Gibbs free energy equation, G = H - TS



Thanks
(edited 6 years ago)
Original post by chem revision
I meant y=mx+c in the title

Can someone explain to me how to apply the equation of a straight line to the Gibbs free energy equation, G = H - TS



Thanks


Your variable is T (hence that is the 'x'...)

Hence -1*(delta S) is m (the gradient)

And deltaH is the c term.

May help to swap rouund to write delta G = -delta S * T + delta H.
Original post by Kevin De Bruyne
Your variable is T (hence that is the 'x'...)

Hence -1*(delta S) is m (the gradient)

And deltaH is the c term.

May help to swap rouund to write delta G = -delta S * T + delta H.


cheers mate

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