Since it's hot and alcoholic KOH, it implies elimination.
Draw out the full mechanism for it, the :OH- attacks a hydrogen on the adjacent carbon to the carbon with the chlorine attached. Water is produced, a double bond forms and the chlorine detaches.
Since there are 3 carbons with hydrogen around the carbon with the chlorine attached, you will get 3 possible products from this reaction. One of the products will be 3-methylhex-2-ene.