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why is my answer wrong? c3 trig question

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cot^2(x) +1=cosec^2(x)
use that identity from the start
Reply 2
I am still looking for where you went wrong, but i would say it is better to use identity cot^2(x)=cosec^2(x)-1 and then get a quadratic equation of cot
then put into double brackets after simplifying
Reply 4
just remind you the denominator=0 will never be considered
Original post by Synikk
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In addition to above, don't set the denominator as 0. What happens when you divide by 0?
Reply 6
edit: I understand how to do it with the identity and that it's easier, i already did it that way but was exploring another way

Thanks for the responses, i realised my mistake with the numerator (i missed two values that were in range with sin 3(theta) = 1/3. But can someone please explain to me why my equating my denominator to zero is wrong?
Original post by Synikk
edit: I understand how to do it with the identity and that it's easier, i already did it that way but was exploring another way

Thanks for the responses, i realised my mistake with the numerator (i missed two values that were in range with sin 3(theta) = 1/3. But can someone please explain to me why my equating my denominator to zero is wrong?


Try dividing something by 0 and see if you get 0
Reply 8
Original post by RDKGames
Try dividing something by 0 and see if you get 0


ah i see im getting = 0 confused with no solution. Thanks!
looks like other than the dividing by zero looks right

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