The Student Room Group

FACTORISING, which type do i use, when to find value of x and when to not??

Scroll to see replies

Reply 20
You're correct! Looking back through all my wokring i seemed to have made the stupid mistake of 3x x 8=28x instead of 24x ! :doh::colondollar: Thanks for your help everyone!
Original post by Notnek
You should get 0 = 14x^2 - 41x - 3.

Have another go and please post all your working if you get stuck. Also, for future questions please always post the original question and your full attempt.
Reply 21
Okay we have:

Ax2+Bx+C=0. Ax^{2} + Bx + C = 0.

As others have stated, we have methods of finding values of x including:
- Quadratic equation,

- Completing the square.

However, as we have some large values we can try inspection.

-------------------------------------------------------------------------------------------------------------------

For inspection, we could try (kx+l)(mx+n)=(km)x2+(lm+kn)x+ln. (kx + l) (mx + n) \, = \, (km)x^{2} + (lm+kn)x + ln.

We need:

- ln = C

- lm +kn = B,

- km = A.

----------------------------------------------------------------------------------------------

For your equation: 14x241x3, 14x^{2} - 41x - 3,

Try: (14x+a)(x+b) (14x + a)(x+b) .

We need:

- ab = -3, (a=-1 and b = 3 ? or a=1 and b = -3 ? or a=3 and b=-1 ? ...)

- a + 14b = -41.

Are you able to carry on from here?
(edited 6 years ago)
Reply 22
Another method you can try (learned this here on TSR) is:

14x241x3. 14x^{2} - 41x - 3.

Multiply by the coefficient of x2 x^{2} :

(14)14x2(14)41x(14)3, (14)14x^{2} - (14)41x - (14)3,

Let z=14x z = 14x :

z241z42 z^{2} - 41z - 42 .

Then factorise (remembering to divide by 14 at the end).

Are you able to carry on with this?

Quick Reply

Latest