The Student Room Group

Fun(ction) question

Hi, can someone check my working out for this please?

And also clarify if I substitute the x values into the 1st or 2nd equation (written in red on the image)

56D67A19-F01C-4D41-AF9B-8639731ACEAB.jpg.jpeg

Thank you
Reply 1
Original post by subbhy
Hi, can someone check my working out for this please?

And also clarify if I substitute the x values into the 1st or 2nd equation (written in red on the image)


Thank you


You should show how you got the x values. What does the rest of your question mean?
(edited 7 months ago)
IMG_5307.jpeg
Think of it like your have 2 graphs
2f(x) and f(0.5x)
You want to find when they intersect so you set them equal to eachother to find if they have the same x coordinate
Than you sub the x values to those graphs, 2f(x) or f(0.5x)
As they intersect, they both give the same y values
Original post by subbhy
Hi, can someone check my working out for this please?

And also clarify if I substitute the x values into the 1st or 2nd equation (written in red on the image)

56D67A19-F01C-4D41-AF9B-8639731ACEAB.jpg.jpeg

Thank you
Reply 3
Original post by Muttley79
You should show how you got the x values. What does the rest of your question mean?


Yes I normally would but just to make the working out easier to follow I omitted it- just used the quadratic formula and then substituted it into equation 1
Reply 4
Original post by BankaiGintoki
IMG_5307.jpeg
Think of it like your have 2 graphs
2f(x) and f(0.5x)
You want to find when they intersect so you set them equal to eachother to find if they have the same x coordinate
Than you sub the x values to those graphs, 2f(x) or f(0.5x)
As they intersect, they both give the same y values


Thank you so much, I always forget this!
Reply 5
Original post by subbhy
Yes I normally would but just to make the working out easier to follow I omitted it- just used the quadratic formula and then substituted it into equation 1


It factorises though - not sure why youve gone further as it's solved!
Reply 6
Original post by Muttley79
It factorises though - not sure why youve gone further as it's solved!


How do you mean?
Sum of 3 and product of -7/4?
Reply 7
Original post by subbhy
How do you mean?
Sum of 3 and product of -7/4?


x4 gives 7x^2 + 12x - 4 = 0
(7x - 2)(x + 2) = 0
x = 2/7 or x = -2 end of question
Reply 8
Original post by Muttley79
x4 gives 7x^2 + 12x - 4 = 0
(7x - 2)(x + 2) = 0
x = 2/7 or x = -2 end of question


Right thanks, I didn’t see it like that.

Do you have any recommendations for trying to spot quicker ways of doing stuff because I always sort of make it harder than it needs to be.
IMG_5310.jpeg
She meant you could work out the factors by simplifying the equation instead of using the quadric formula
Original post by subbhy
How do you mean?
Sum of 3 and product of -7/4?
(edited 7 months ago)
Original post by BankaiGintoki

He meant you could work out the factors by simplifying the equation instead of using the quadric formula


She ...
Original post by subbhy
Right thanks, I didn’t see it like that.

Do you have any recommendations for trying to spot quicker ways of doing stuff because I always sort of make it harder than it needs to be.


Experience ... unlikely to be a decimal as it does not say the accuracy required.
Original post by Muttley79
She ...


Sorry
Reply 13
Original post by BankaiGintoki
IMG_5310.jpeg
He meant you could work out the factors by simplifying the equation instead of using the quadric formula


Thanks, it’s a different method than I’m used to!
Reply 14
Original post by Muttley79
She ...


Original post by BankaiGintoki
Sorry


He actually so all good
Original post by BankaiGintoki
Sorry

It's fine - be careful how you write your '4' in exams - they look like 7s or ys
Original post by subbhy
He actually so all good


I think the 'he' was directed at me :smile:
Reply 17
Original post by Muttley79
I think the 'he' was directed at me :smile:


Haha it’s all good! Thanks for the help

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