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1. Calculate the path difference between the two aerials

distance from 2 aerials is 2.5m
phase difference is 114 degrees
frequency is 125x10^6 is
have found out path difference to be 0.32 lamda by finding phase difference to be 0.64 and then I'm fed it for phase difference but don't know where to go from there
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4. (Original post by Hasham123)
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I'm not clear what you're trying to do.

Are you trying to convert 0.32 lamda to metres?

If that's the case, just use the wave equation to change that frequency to a wavelength.

If that's not what you're trying to do, can you clarify (or post the full question) so someone here can help?
5. don't know either but don't I need wave speed to get get wavelength from frequency
6. If these are radio waves then the speed is 3 x 10 ^ 8
7. (Original post by Hasham123)
Calculate the path difference between the two aerials

distance from 2 aerials is 2.5m
phase difference is 114 degrees
frequency is 125x10^6 is
have found out path difference to be 0.32 lamda by finding phase difference to be 0.64 and then I'm fed it for phase difference but don't know where to go from there
The first four lines are part of the question right? You found the phase difference as 0.64 and path difference as 0.32. Alright, pls show your working. Do you by chance have the true values for the path difference?

Anyways, I've worked it out though Im not sure if it is the correct answer.

That's the formula I've used.
First I found the wavelength of the signal using eqn: λ= v/f where v= 3E8 , f is mentioned.
λ= 2.4 m

Then I converted the phase difference from 114 degrees into fraction form which is :-
Attachment 729278729284

so yeah Im getting the path difference as 0.76 m Is it right?
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