The Student Room Group

curious on matrices

Why is it that if a 2 by 2 matrix can commute with both
(1 0
0 0) and
(1 1
0 0)
then it can commute with every 2 by 2 matrix?
Original post by Iconic_panda
Why is it that if a 2 by 2 matrix can commute with both
(1 0
0 0) and
(1 1
0 0)
then it can commute with every 2 by 2 matrix?


What have you tried?
oh i discovered that in order to commute with
(1 0
0 0) then it has to be diagonal matrix
in order to commute with
(1 1
0 0) you have to have a matrix where
(a b
0 a-b)
i set them equal to each other and I got general 2 by 2 matrix
(a 0
0 a) and i found out this can commute with every 2 by 2.
This isn't a coincidence right?
Original post by ghostwalker
What have you tried?
Original post by Iconic_panda
oh i discovered that in order to commute with
(1 0
0 0) then it has to be diagonal matrix
in order to commute with
(1 1
0 0) you have to have a matrix where
(a b
0 a-b)
i set them equal to each other and I got general 2 by 2 matrix
(a 0
0 a) and i found out this can commute with every 2 by 2.
This isn't a coincidence right?


Well
(a 0
0 a)

is simply "a" times the identity matrix, hence the commutability (if that's a real word).
ahh so theres nothing to do with the fact that it commutes with the other two matrices. thank!
Original post by ghostwalker
Well
(a 0
0 a)

is simply "a" times the identity matrix, hence the commutability (if that's a real word).
Original post by ghostwalker
Well
(a 0
0 a)

is simply "a" times the identity matrix, hence the commutability (if that's a real word).


Commutativity?
Original post by Iconic_panda
ahh so theres nothing to do with the fact that it commutes with the other two matrices. thank!


Well there is. The fact that a matrix commutes with the other two implies that it is of the form aIaI for some real a.
ohh yeah that makes sense thanks!
Original post by ghostwalker
Well there is. The fact that a matrix commutes with the other two implies that it is of the form aIaI for some real a.

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