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AQA A Level Chemistry Paper 2 11th June Unofficial Markscheme

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You had to include it and it had to be sealed at the top :/
There is still an opening at the end where the distillate leaves so no pressure builds up
Original post by Spiker149
I didn't add a thermometer, doesn't that build up pressure?
Original post by jamesctu
do you know how to do this question


((2x10-2)-(1.84x10-2))/5

((0.5x10-2)-(0.34x10-2))/5
i drew the structure of a dipeptide and looked at what groups would reform (NH2 and COOH) so i decided that water could be used but im not sure if this is correct
Original post by Lucallah
First Google result says NaOH can't be used to hydrolyse proteins as it breaks down the amino acids, so I'm pretty sure that would be wrong. Using HCl is the process included in the spec but the equation only shows H+ so I feel like the choice of acid isn't too important.
Reply 103
I wrote water too. Mainly because hydro was in the name, but also because peptides/polyamides are susceptible to nucleophilic attack from water - this is what makes them biodegradable. So i figured that this may be suitable, because hydrolysis of ester is done by adding water.

I think the main purpose of the acid or alkali is to act as catalyst. I don't remember how many marks the question was, so i don't know if you needed to say both, or with water being amphoteric is enough.
Original post by Zaki1039
i drew the structure of a dipeptide and looked at what groups would reform (NH2 and COOH) so i decided that water could be used but im not sure if this is correct
Original post by 0rg4n1c
((2x10-2)-(1.84x10-2))/5

((0.5x10-2)-(0.34x10-2))/5

H i friend do you know how to answer this question
Reply 105
Original post by jamesctu
H i friend do you know how to answer this question


Convert Ea to J.
Convert T into Kelvin.
Plug into equation and rearrange for A.

I have just started a new thread called A-level Chemistry Paper 2 - Exam Topics / Questions https://www.thestudentroom.co.uk/showthread.php?t=5997186 to streamline the unofficial mark scheme answers. If you remember specific questions i would really appreciate it if you could post them there, and I will do my best to answer any questions you have :smile:
Original post by ÷by0
Convert Ea to J.
Convert T into Kelvin.
Plug into equation and rearrange for A.

I have just started a new thread called A-level Chemistry Paper 2 - Exam Topics / Questions https://www.thestudentroom.co.uk/showthread.php?t=5997186 to streamline the unofficial mark scheme answers. If you remember specific questions i would really appreciate it if you could post them there, and I will do my best to answer any questions you have :smile:

how do you rearange it
i converted t into 298k
ea into 96200 J
k=3.46 x 10-8
r=8.31
so far based on paper 1 and 2 difficulty, what do you think the grade boundaries potentially will be? Was 204 for an A in 2017 but those papers were easier than 2018 which was 198 for an A.
Why did I get like 136% or something for the yield I assumed impurities wow I really messed this one up
Original post by Utd4life0101
so far based on paper 1 and 2 difficulty, what do you think the grade boundaries potentially will be? Was 204 for an A in 2017 but those papers were easier than 2018 which was 198 for an A.


Not sure but I imagine lower than last year. Probably not by much. 79-80% for A* 65-67% for an A. That’s just my guess though depends on paper 3 as well
Reply 110
Original post by jamesctu
how do you rearange it
i converted t into 298k
ea into 96200 J
k=3.46 x 10-8
r=8.31


Work out the value for e^-(Ea/RT) which is just a number, lets say that = x, which you can store in your calculator. You now have k=Ax, => A = k/x.
yeah hopefully. any predictions for paper 3? and for mcqs any advice?
Original post by Gnuyheatmik
Not sure but I imagine lower than last year. Probably not by much. 79-80% for A* 65-67% for an A. That’s just my guess though depends on paper 3 as well
do you know what the answer was friend
Original post by ÷by0
Work out the value for e^-(Ea/RT) which is just a number, lets say that = x, which you can store in your calculator. You now have k=Ax, => A = k/x.
Reply 113
2.57x10^9 s-1
Original post by jamesctu
do you know what the answer was friend
for the nucleotide components of cytosine, did you need to circle the cytosine as well? i thought it said the other components that make it up... 2-deoxyribose etc and it wouldve overlapped with my hydrogen bonds.
Reply 115
I thought the question asked you to circle the components that make up the nucleotide containing cytosine. nucleotides do have 3 components, but cytosine was stated in the question. Tbh, I'm not a biologist so i don't really know.
Original post by Utd4life0101
for the nucleotide components of cytosine, did you need to circle the cytosine as well? i thought it said the other components that make it up... 2-deoxyribose etc and it wouldve overlapped with my hydrogen bonds.
Original post by Utd4life0101
yeah hopefully. any predictions for paper 3? and for mcqs any advice?


not really sure what will be on it tbh. i doubt there will be many organic practicals as there were a few today. electrochemical cells will definitely be on as it hasnt been on any of the papers so far. for mcqs i just do loads of practise questions in timed conditions
guys -
how did people work out the molecular formula for the golf ball question ?
in total how many marks do those nmr one/two markers add up to?
Reply 119
i think you already know mr = 118, you know it has 2 -COOH groups. It is not branched.

Mass COOH = 12 + 32 + 1 = 45
x2 = 90
Mr - 90 = 28
there must be CH2 in between groups, CH2 has mass 14.
28/14 = 2
=> HOOCCH2CH2COOH

Please rep if this was helpful !

Original post by naimahh14
guys -
how did people work out the molecular formula for the golf ball question ?

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