Chemistry 1C june 2023 exam 22nd May

What did you get for x

10

How did you I got 4

Subtract final mass from mass of crucible to get mass of anhydrous sodium sulfate
Subtract final mass from initial to get mass of water evaporated
Do mass/Mr for both to find moles of each
put it in a ratio of water:sodium sulfate (I think it was 0.25:0.025) and divide by the smallest number
you will get a ratio of 10:1 so x = 10

Did you guys get around -3594kJ/mol for the ΔH 5 marker?

What did you get for x

Does anyone else think the grade boundaries could be 90% + this year? That paper was not very difficult.

Subtract final mass from mass of crucible to get mass of anhydrous sodium sulfate
Subtract final mass from initial to get mass of water evaporated
Do mass/Mr for both to find moles of each
put it in a ratio of water:sodium sulfate (I think it was 0.25:0.025) and divide by the smallest number
you will get a ratio of 10:1 so x = 10

Yes around that number it had 3594.333 as well

yea i got -3594.13 i think cus i rounded to 0.00409 moles

I didn't round it, just stored it in my calc and got -3593.33. Most people in my school got that as well... Doubt they will mark down for rounding early tho

i got 10 did you?

No but most people go that I got 4. What was the mass of the water

I think it was 4.5 because of 8.05-3.55 thus water was 4.5 and then divide it by mr to get 0.25 and the 0.25 divide by 0.025 to get 10 moles with it basically being a 1:10 ratio

Oh I did do that what was the sodium part ?