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    Basically,

    anti clockwise moment = clockwise moment

    moment = force x perpendicular distance between the line of action of force and the pivot

    e.g.

    total clockwise moment = anti clockwise moment
    

12 N \times 0.15m = F \times (0.4-0.15)m



F = \dfrac{12 N \times 0.15}{0.25m}



F = 7.2n

    But, if clockwise moment = anti clockwise moment

    shouldnt they both be 7.2 or 1.8 :confused:
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    The forces can be different but the moments must be the same.

    So the moment clockwise is 12N * 0.15m = 1.8Nm
    And the anticlockwise moment is 7.2N * 0.25m = 1.8Nm

    So the moments are both the same.
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    Got it right now. (I think :P)
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    oh crap.. whoops.. it was asking me to work out the force and not the moment *stupid moment*
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    HaHa. We all do it.
 
 
 

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