Original post by myii
heyy guys i got a quick question:
what is modelled by each term in the Van der Pol equation??
what is modelled by each term in the Van der Pol equation??
What do you think each term models?
Original post by RDKGames
What do you think each term models?
what does it mean by modelling?
Original post by myii
what does it mean by modelling?
Each term represents something in a physical sense. For instance, the term is displacement, what does model ??
Think about what the middle term models in a similar fashion.
Original post by RDKGames
Each term represents something in a physical sense. For instance, the term is displacement, what does model ??
Think about what the middle term models in a similar fashion.
Think about what the middle term models in a similar fashion.
ohh okay for example does x with a dot on the top represent the displacement derivative?
Original post by myii
ohh okay for example does '\ddot{x}' represent the displacement derivative?
is standard notation for the second derivative of with respect to time.
If it's not displaying properly (i.e. you instead see code for \ddot{x}) then you should view this thread on a better web browser.
Original post by RDKGames
is standard notation for the second derivative of with respect to time.
If it's not displaying properly (i.e. you instead see code for \ddot{x}) then you should view this thread on a better web browser.
If it's not displaying properly (i.e. you instead see code for \ddot{x}) then you should view this thread on a better web browser.
ahhh thanks for letting me know so does the notation of 'μ' in the van der pol equation mean a scalar parameter indicating the non-linearity?
Original post by myii
ahhh thanks for letting me know so does the notation of 'μ' in the van der pol equation mean a scalar parameter indicating the non-linearity?
Pretty much, though you can be a bit more specific because the nonlinearity comes from the product .
The is just a parameter denoting the strength of this nonlinearity. It is the damping parameter.
It's also important to realise that the Van der Pol equation is a dimensionless equation. I mentioned above that it has terms representing something in a physical sense, but in any physical application your equation must be dimensionally consistent, hence it makes no sense to add acceleration with displacement . For this reason we non-dimensionalise the model whereby and becomes dimensionless and a parameter pops out in the equation. But the interpretation of each term remains the same in a sense.
Quick Reply
Related discussions
- Help recognising intermolecular forces
- van der waals
- Make it More Sport Shoe-ey !!
- Make it More Virus-ey !!
- Make it More Whale-ey !!
- Make it More Australian Plant-ey !!
- AS Chemistry Multiple choice question help TQ
- dipole dipole vs vanderwaals forces difference
- Make it More Finger-ey !!
- Make it More Digestive System-ey !!
- Make it More Ancient Egypt-ey !!
- Make it More Festival-ey !!
- does the charge cloud get bigger as number of electrons increase?
- Boiling point of halogenoalkanes
- Chemistry - organics
- Make it More Foot-ey !!
- Physics GCSE
- Make it More Fictional Detective-ey !!
- Which former players would excel in today's game?
- Psychology book recommendations
Latest
Trending
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
Trending
Last reply 3 days ago
Did Cambridge maths students find maths and further maths a level very easy?Last reply 2 weeks ago
Edexcel A Level Mathematics Paper 2 unofficial mark scheme correct me if wrongMaths
71
