Chemistry ( A level )

1.20 dm3 of ammonia gas were dissolved in water to form 200 cm3 of aqueous alkali at room temperature and pressure.

(i) Use the Data Booklet to calculate how many moles of NH3(g) were dissolved.

Reply 1

hoosie

Original post by Sasha Shasha

1.20 dm3 of ammonia gas were dissolved in water to form 200 cm3 of aqueous alkali at room temperature and pressure.

(i) Use the Data Booklet to calculate how many moles of NH3(g) were dissolved.

Hint: The molar volume of a gas is the volume of one mole of the gas at a given temperature and pressure. At STP, one mole (6.02 × 10^23 particles) of any gas occupies a volume of 22.4 L Any gas occupies 22.4 L at standard temperature and pressure (0°C and 1 atm). 1dm^3 = 1L

Reply 2

Sasha Shasha

Its rtp and I dont understand , can you explain me in detail ?
:frown:

Reply 3

Sasha Shasha

Is 1.20/24 =1/20 the answer

Reply 4

hoosie

Because it is RTP and not STP use a value of 24.0 dm3 at room temperature and pressure (taken as about 20°C and 1 atmosphere). So your answer is correct.

Reply 5

Sasha Shasha

Original post by hoosie

Because it is RTP and not STP use a value of 24.0 dm3 at room temperature and pressure (taken as about 20°C and 1 atmosphere). So your answer is correct.