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Newton’s Second Law equation of motion

I have no idea on how I’m meant to answer this question I’ve done the first one and got it right I’d appreciate any help, I’ll post the question below
Reply 1
image.jpg
1ii)
image.jpg
Those are my answers for i)
Original post by A0W0N
I have no idea on how I’m meant to answer this question I’ve done the first one and got it right I’d appreciate any help, I’ll post the question below

Do you live in Australia by any chance?
Reply 3
The net force on each mass must be the difference between the tension and the weight. So
ma = ...
For each of the masses.
Reply 4
If got two equations and for part three got two answers which make sense but the answer book says the answers are: 3.27ms^-2 and 1.31N
image.jpg
Reply 5
Original post by A0W0N
If got two equations and for part three got two answers which make sense but the answer book says the answers are: 3.27ms^-2 and 1.31N
image.jpg

At the start, a is both positive and negative in your two equations.
One must be
T - mg
And the other
mg - T
The tension is nonzero and must raise one block and slow down the other.
(edited 4 years ago)
Reply 6
Original post by mqb2766
At the start, a is both positive and negative in your two equations.
One must be
T - mg
And the other
mg - T
The tension is nonzero and must raise one block and slow down the other.

Ok I get it thanks
(edited 4 years ago)
Reply 7
image.jpg
What have I done wrong here?
Reply 8
Is this iv)? If so you need to find the time to hit the ground (distance s).
Which suvat are you using and what values?
Reply 9
Original post by mqb2766
Is this iv)? If so you need to find the time to hit the ground (distance s).
Which suvat are you using and what values?

u=0
V=0
A=3.27

V=u+at
And i got t=0 which is incorrect these are all above in the photo above:smile:
Original post by A0W0N
u=0
V=0
A=3.27

V=u+at
And i got t=0 which is incorrect these are all above in the photo above:smile:

There is no distance in the equation? You need to work out the time for the mass to drop/ travel a certain distance.

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