# Mechanics- velocity and acceleration

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#1
Iam getting the ans as 63m, but the ans in the text book is 62m. Pls help its the 13th question
Last edited by Shas72; 1 month ago
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1 month ago
#2
Not sure about Chris's acceleration. Or the time correction.
Last edited by mqb2766; 1 month ago
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#3
(Original post by mqb2766)
Not sure about Chris's acceleration. Or the time correction.
Chris acceleration would be 2m/s^2
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#4
(Original post by mqb2766)
Not sure about Chris's acceleration. Or the time correction.
When t=8, and v=16m/s, a=2m/s^2.
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1 month ago
#5
(Original post by Shas72)
Chris acceleration would be 2m/s^2
You’ve written 1.6 (even though your calculation is using 2 anyways)

Is it definitely 62 in the book?
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#6
(Original post by GabiAbi84)
You’ve written 1.6 (even though your calculation is using 2 anyways)

Is it definitely 62 in the book?
Yeah
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#7
(Original post by GabiAbi84)
You’ve written 1.6 (even though your calculation is using 2 anyways)

Is it definitely 62 in the book?
The distance is 62m and for the second question time is 23.1s
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1 month ago
#8
(Original post by Shas72)
The distance is 62m and for the second question time is 23.1s
Have you got the time correction sorted?
Draw the velocity time graph if necessary.
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#9
I don't understand the time for chris. is it (t-5) or (t+5)
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#10
if Bradley t=0, Chris starts 5s later than Bradley will be t+5
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1 month ago
#11
(Original post by Shas72)
I don't understand the time for chris. is it (t-5) or (t+5)
You've done this before. Tbh, you just need to see how long he spends at constant speed. It's easy to reason.
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1 month ago
#12
(Original post by Shas72)
The distance is 62m and for the second question time is 23.1s
How can the second part be 23.1s when the first part proved that Chris hadn’t overtaken him by the time he started decelerating at 50s?
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#13
I know and you only taught me that it will be t-5.
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#14
so I need to first find the time for chris
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1 month ago
#15
(Original post by Shas72)
I know and you only taught me that it will be t-5.
Ive tried to get you to think more, sketch and respond slower.
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#16
ok sure. thanks!!
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1 month ago
#17
(Original post by Shas72)
ok sure. thanks!!
You don't really need t+/-5. You are given the time intervals.
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#18
(Original post by mqb2766)
You don't really need t+/-5. You are given the time intervals.
Ok thanks! Will do that
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#19
(Original post by mqb2766)
You don't really need t+/-5. You are given the time intervals.

Last edited by Shas72; 1 month ago
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1 month ago
#20
(Original post by Shas72)

But they don't start at the same time.
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