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nuclear physics a level qu

if anyone can help me in part three that would be much appreciated. thank you in advance. I'm not sure how i can

the equation for the reaction is (the number at the top is the mass number for each, and below proton number)
2 3 4 1
H + H goes to HE + n + energy
1 1 2 0

the amount of energy generated is 2.82x10^-12 J
the energy generated is shared between the helium-4 nucleus and the neutron. calculate what percentage of the energy released is gained by the neutron. assume that the initial momentum of the products is zero
(edited 3 years ago)
KE(n)/KE(He)=m(He)/m(n)
so KE(n)/KE(He)=4 and the neutron will have 4 times the amount of energy as the helium nucleus, or 4/5 of the total energy
not sure if that’s exactly what you’re looking for but i hope it helps!

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