The Student Room Group
Reply 1
Write the LHS out in terms of sin and cos, and then put it over a common denominator
i.e. a/b + b/a = (a^+b^2) /(ab)

....that gets you the answer.
Reply 2
Those three lines mean it is always equal to. Try turning cosec(2x) in something with only x (not 2x), using the sin double angle formula.
Reply 3
TheDuck
Write the LHS out in terms of sin and cos, and then put it over a common denominator
i.e. a/b + b/a = (a^+b^2) /(ab)

....that gets you the answer.


Thanks, but it's: sinx/cosx + 1/tanx

To get it in terms of sin/cos would I put the second part as 1/(sinx/cosx)? Not sure how that would work :confused:
Waheyyyy
Thanks, but it's: sinx/cosx + 1/tanx

To get it in terms of sin/cos would I put the second part as 1/(sinx/cosx)? Not sure how that would work :confused:

yes thats correct ... so its cos/sin... multiply through and then ull get ur answer
Reply 5
sin(x)cos(x)+cos(x)sin(x)=2sin(2x)\frac{sin(x)}{cos(x)}+\frac{cos(x)}{sin(x)}=\frac{2}{sin(2x)}

edit: darkness, you beat me to it. Damn you, LaTeX!

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