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I dont understand how to use CAST diagrams with reciprocal trigonometric ratios

Screenshot 2022-08-18 4.09.53 PM.pngI was looking at the edexcel year 2 pure textbooks and they are doing CAST diagrams differently??
(edited 1 year ago)
Original post by val7322
Screenshot 2022-08-18 4.09.53 PM.pngI was looking at the edexcel year 2 pure textbooks and they are doing CAST diagrams differently??


What are you saying is different? Perhaps it would be been more "usual" in cast to say
cos(210) = cos(150)
or
cos(210) = - cos(-30)
but both reduce to
cos(210) = -cos(30).
But its fairly clear the triangles (30-60-90) in the two quadrants (1 and 3) are equivalent apart from the sign change on the x-axis, so cos() flips sign between 30 and 210.
(edited 1 year ago)
Reply 2
how comes this inverse rule isnt applicable to sec 60?

Original post by mqb2766
What are you saying is different? Perhaps it would be been more "usual" in cast to say
cos(210) = cos(150)
or
cos(210) = - cos(-30)
but both reduce to
cos(210) = -cos(30).
But its fairly clear the triangles (30-60-90) in the two quadrants (1 and 3) are equivalent apart from the sign change on the x-axis, so cos() flips sign between 30 and 210.
Original post by val7322
how comes this inverse rule isnt applicable to sec 60?


There is nothing special about sec/cosec/cot, cast applies to them just by interpreting them as cos/sin/tan.
sec(60) = 1/cos(60) = ...
it does work, though thats a fairly trivial example as its in quadrant 1.
(edited 1 year ago)
Reply 4
how comes its not inversed to be cos 30 (just like you did with the other one)

Original post by mqb2766
There is nothing special about sec/cosec/cot, cast applies to them just by interpreting them as cos/sin/tan.
sec(60) = 1/cos(60) = ...
it does work, though thats a fairly trivial example as its in quadrant 1.
Original post by val7322
how comes its not inversed to be cos 30 (just like you did with the other one)


For the first one
sec(210) = 1/cos(210) = ...
so do cast on cos(210) then take the reciprocal to get back to sec(210).

For the second
sec(60) = 1/cos(60) = ...
so its simply the reciprocal of cos(60) as there is no need to use cast to reason about the sign.

Its the same in both cases.
(edited 1 year ago)
Reply 6
thans

Original post by mqb2766
For the first one
sec(210) = 1/cos(210) = ...
so do cast on cos(210) then take the reciprocal to get back to sec(210).

For the second
sec(60) = 1/cos(60) = ...
so its simply the reciprocal of cos(60) as there is no need to use cast to reason about the sign.

Its the same in both cases.
Reply 7
I'm also stuck on this quesiton, wheres the -1/2 coming from?

Original post by mqb2766
For the first one
sec(210) = 1/cos(210) = ...
so do cast on cos(210) then take the reciprocal to get back to sec(210).

For the second
sec(60) = 1/cos(60) = ...
so its simply the reciprocal of cos(60) as there is no need to use cast to reason about the sign.

Its the same in both cases.

Screenshot 2022-08-19 8.02.46 PM.png
-cos(pi/3) = -1/2
if thats where you mean? You could simply evalate on your calcuator if unsure.
Reply 9
Ohhhhhh i didn't know I had to use my calculator

Original post by mqb2766
-cos(pi/3) = -1/2
if thats where you mean? You could simply evalate on your calcuator if unsure.
Original post by val7322
Ohhhhhh i didn't know I had to use my calculator


You shouldnt have to, its a standard trig value you should know from gcse.
cos(pi/3) = cos(60) = ...

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