https://www.quora.com/profile/Bravewarrior/p-147186485

Here is the question and its solution. I am stuck on part c. Can someone please explain how they got theta as the value shown in the solution? Thanks!

Here is the question and its solution. I am stuck on part c. Can someone please explain how they got theta as the value shown in the solution? Thanks!

Original post by mqb2766

Its a circle of radius 9 between the angles -pi/6 and pi/2. So the arc length is

9*(pi/2 + pi/6)

9*(pi/2 + pi/6)

Thank you! I was struggling to understand it visually, but I guess you just have to look at the given restriction/interval?

Original post by pigeonwarrior

Thank you! I was struggling to understand it visually, but I guess you just have to look at the given restriction/interval?

The "t" parametric varaible corresponds to the angle "theta". Its the central idea in the question about describing a circle parametrically so roughly

x = r*cos(t)

y = r*sin(t)

(with a translation / nonzero centre) rather than cartesian

x^2+y^2=r^2

Parts a) and b) are all about making you view it as a circle, then the arc length should be straightforward.

(edited 3 months ago)

Original post by mqb2766

The "t" parametric varaible corresponds to the angle "theta". Its the central idea in the question about describing a circle parametrically so roughly

x = r*cos(t)

y = r*sin(t)

(with a translation / nonzero centre) rather than cartesian

x^2+y^2=r^2

Parts a) and b) are all about making you view it as a circle, then the arc length should be straightforward.

x = r*cos(t)

y = r*sin(t)

(with a translation / nonzero centre) rather than cartesian

x^2+y^2=r^2

Parts a) and b) are all about making you view it as a circle, then the arc length should be straightforward.

Yup, that makes sense 🙂 thank you!

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