Statics of a particle

What are you trying to do? I'm not sure I follow.

Reply 2

Juno

20

It's theta, not feta. That's a type of cheese

Reply 3

OP

juno_the

It's theta, not feta. That's a type of cheese

lol

Reply 4

OP

Nima

If you tell me whether P and Q act towards or away from the origin, then I can answer the question I think.

It doesn't say, but my feeling is that P acts along the x axis, whereas Q acts along the y axis and makes an angle of 60 on the x axis/

Reply 5

The question already gives you the angle. Why are you trying to find another one?

Reply 6

OP

dvs

The question already gives you the angle. Why are you trying to find another one?

I am trying to find the inner angle of the triangle , I will draw picture of what I think the question looks like, bare with me for a sec.

Reply 7

Ohhh nevermind. I didn't read the question carefully, sorry!

Reply 8

STATICSOFPARTICLEQ.JPG5.1KB

OP

DOJO

I am trying to find the inner angle of the triangle , I will draw picture of what I think the question looks like, bare with me for a sec.

This is my interpretation of the Question

Reply 9

The resultant force equals sqrt[37] N. Apply the sine rule to get:
(sinT)/3 = (sin120)/sqrt[37] [120 is from 180-60 -- draw the diagram and complete a parallelogram]

sinT = 3(sin120)/sqrt[37]
T = 25.3

Reply 10

OP

dvs

The resultant force equals sqrt[37] N. Apply the sine rule to get:
(sinT)/3 = (sin120)/sqrt[37] [120 is from 180-60 -- draw the diagram and complete a parallelogram]

sinT = 3(sin120)/sqrt[37]
T = 25.3

I am so sure I did that, I don't know why I keep getting 0.427121098

Reply 11

Here's my interpretation. (I appologize for the crappy drawing.)

123.JPG10.8KB

Reply 12

OP

dvs

Here's my interpretation. (I appologize for the crappy drawing.)

Np, but it looks like our methods are both correct. I have no clue that when I do

sinT = 3(sin120)/sqrt[37]
T = 25.3

It comes out as 0.427121098 and not 25.3. My calc is set in degrees mode.

Reply 13

DOJO

It comes out as 0.427121098 and not 25.3. My calc is set in degrees mode.

I really should start reading the entire post before replying...

First time, I read that the question only wanted you to find the resultant force, so I got confused when I saw you trying to find an angle. Second time, I thought you didn't know how to do the question. And now, I finally know what's wrong... You're finding sinT, and not T. Try finding arcsin(0.427121098) (inverse sine). If your calculator's one of those scientific Casios, press shift and sin, then = (after you get 0.427121098 on the screen).

Reply 14